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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: The philosophy of computation reformulates existing ideas on a
 new basis ---x86 code is a liar?
Date: Mon, 11 Nov 2024 16:25:55 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
Message-ID: <4eebe767dc236a7770566fc1593aae14a38cb085@i2pn2.org>
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Am Mon, 11 Nov 2024 08:58:02 -0600 schrieb olcott:
> On 11/11/2024 4:54 AM, Mikko wrote:
>> On 2024-11-09 14:36:07 +0000, olcott said:
>>> On 11/9/2024 7:53 AM, Mikko wrote:
>>>> On 2024-11-08 14:41:57 +0000, olcott said:
>>>>> On 11/8/2024 3:57 AM, joes wrote:
>>>>>> Am Thu, 07 Nov 2024 15:56:31 -0600 schrieb olcott:
>>>>>>> On 11/7/2024 3:24 PM, joes wrote:
>>>>>>>> Am Thu, 07 Nov 2024 10:31:41 -0600 schrieb olcott:
>>>>>>>>> On 11/7/2024 5:56 AM, Richard Damon wrote:
>>>>>>>>>> On 11/6/24 11:39 PM, olcott wrote:

>>>>>>> There <is> a key distinguishing difference in the behavior of DDD
>>>>>>> emulated by HHH and DDD emulated by HHH1 or directly executed. It
>>>>>>> is ridiculously stupid to simply ignore this for three f-cking
>>>>>>> years.
>>>>>> That difference is not due to DDD.
>>>>> The semantic property of the finite string pair: HHH/DDD
>>>>> unequivocally entails that DDD never reaches its final halt state.
>>>> No, it does not. You might say that the semantic property of the
>>>> finite string "Olcott is an idiot" unequvocally entails that Olcott
>>>> is an idiot but it does not.
>>> The semantic property of the finite string pair: HHH/DDD unequivocally
>>> entails that DDD never reaches its final halt state WITHIN THE
>>> SEMANTICS OF THE X86 LANGUAGE.
>> The expression "The semantic property" is incorrect when it is not
>> clear from context which semantic property is meant. Note that a string
>> per se does not have semantic properties, they all come from
>> interpretrations.
> That you pretend to not understand my clear words does not mean that my
> words are not clear.
Sigh. Mikko didn’t write anything about not understanding. Also, way to
blame the receiver for bad communication.

> The fact that DDD defines a pathological relationship with HHH cannot be
> simply ignored and must be accounted for.
Same as any other kind of relationship.

> The actual computation itself
> does involve HHH emulating itself emulating DDD. To simply pretend that
> this does not occur seems dishonest.
Which is what you are doing: you pretend that DDD calls some other HHH
that doesn’t abort. But the HHH that simulates DDD does in fact abort
and not simulate itself aborting.

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.