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From: joes <noreply@example.org>
Newsgroups: sci.math
Subject: Re: collective and individual removal
Date: Thu, 1 May 2025 15:11:15 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
Message-ID: <532b434928d2ea6214456beb5e869e99df037b87@i2pn2.org>
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Am Wed, 30 Apr 2025 22:34:26 +0200 schrieb WM:
> On 30.04.2025 15:15, joes wrote:
>> Am Wed, 30 Apr 2025 14:43:46 +0200 schrieb WM:
>>> On 29.04.2025 15:34, FromTheRafters wrote:
>>>> on 4/29/2025, WM supposed :
>>>>> On 29.04.2025 01:30, FromTheRafters wrote:
>>>>>> WM formulated the question :
>>>>>
>>>>>>> That is wrong because you cannot remove all natural numbers by
>>>>>>> removing only definable numbers
>>>> Each and every non-initial natural number is *DEFINED* as being one
>>>> more than the previously defined one.
>>> This chain fails. Otherwise you could remove all numbers by removing
>>> only defined ones. But that is impossible.
>> It could only fail if one didn't have a successor.#
> It fails. It is impossible to remove all natural numbers by defining
> each one.
No. It is possible, every one has a successor, there are none that don't,
those are all naturals, numbers that don't aren't naturals.

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.