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Path: ...!weretis.net!feeder9.news.weretis.net!i2pn.org!i2pn2.org!.POSTED!not-for-mail From: hertz778@gmail.com (rhertz) Newsgroups: sci.physics.relativity Subject: Re: Relativity is a pseudoscience II. The Hafele-Keating HOAX, Date: Fri, 20 Sep 2024 01:08:53 +0000 Organization: novaBBS Message-ID: <6018942957f9aacb3aea5fadde7a79aa@www.novabbs.com> References: <dad338831baa98f3eb1ca50452fd9401@www.novabbs.com> MIME-Version: 1.0 Content-Type: text/plain; charset=utf-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Info: i2pn2.org; logging-data="2708665"; mail-complaints-to="usenet@i2pn2.org"; posting-account="hWiuCAeR3KEZYJfTvV11n0qrRi6oqW/zjvEZQQGun9A"; User-Agent: Rocksolid Light X-Spam-Checker-Version: SpamAssassin 4.0.0 X-Rslight-Site: $2y$10$6QPzJUVBZnajI/wDKLwi1u/lC9c0BNT2aooH/xbkdarUN0FL2Oh4e X-Rslight-Posting-User: f685b96694175b2ad43ead343ead0a9c0082fe88 Bytes: 1810 Lines: 29 *************************************************************** If τ and τ₀ are the respective times recorded by the flying and ground reference clocks during a complete circumnavigation, their time difference, to a first approximation, is given by (τ - τ₀)/τ₀ = -(2RΩv + v²)/2c² ************************************************************** Just a curiosity with this Hafele formula for SR: R = 6,361,000 m Ω = 0.000072921159 rad/sec v = 900 Kmph = 250 m/sec It gives to me a value (τ - τ₀)/τ₀ = -1.638E-12 Accumulating 65 hours flying eastward, it gives (τ - τ₀) = -383.2 nanoseconds for a full eastward flight around the globe. But Hafele published a theoretical SR value of -184 ± 18 nsec, which is almost half the value I calculated using his formula for SR. Can anyone spot my error?