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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: ChatGPT refutes the key rebuttal of my work
Date: Thu, 17 Oct 2024 10:07:27 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Wed, 16 Oct 2024 15:06:01 -0500 schrieb olcott:
> On 10/16/2024 3:02 PM, joes wrote:
>> Am Wed, 16 Oct 2024 14:39:37 -0500 schrieb olcott:
>>> On 10/16/2024 2:33 PM, joes wrote:
>>>> Am Wed, 16 Oct 2024 13:59:58 -0500 schrieb olcott:
>>>>> On 10/16/2024 1:47 PM, joes wrote:
>>>>>> Am Wed, 16 Oct 2024 13:35:01 -0500 schrieb olcott:
>>>>>>> On 10/16/2024 1:06 PM, joes wrote:
>>>>>>>> Am Wed, 16 Oct 2024 12:46:01 -0500 schrieb olcott:
>>>>>>>>> On 10/16/2024 12:27 PM, joes wrote:
>>>>>>>>>> Am Wed, 16 Oct 2024 10:39:21 -0500 schrieb olcott:
>>>>>>>>>>> On 10/16/2024 9:45 AM, joes wrote:
>>>>>>>>>>>> Am Wed, 16 Oct 2024 09:11:22 -0500 schrieb olcott:
>>>>>>>>>>>>> On 10/16/2024 9:01 AM, joes wrote:
>>>>>>>>>>>>>> Am Wed, 16 Oct 2024 08:31:43 -0500 schrieb olcott:
>>>>>>>>>>>>>>> On 10/16/2024 1:33 AM, joes wrote:
>>>>>>
>>>>>>>>>>>>>>> Terminating C functions must reach their "return"
>>>>>>>>>>>>>>> statement.
>>>>>>>>>>>>>> Which DDD does.
>>>>>>>>>>>>> THIS IS ALSO THE INDUSTRY STANDARD DEFINITION It is
>>>>>>>>>>>>> stipulated that *correct_x86_emulation* means that a finite
>>>>>>>>>>>>> string of x86 instructions is emulated according to the
>>>>>>>>>>>>> semantics of the x86 language beginning with the first bytes
>>>>>>>>>>>>> of this string.
>>>>>>>>>>>> You are not simulating the given program, but a version that
>>>>>>>>>>>> differs in the abort check.
>>>>>>>>>>> HHH is correctly emulating (not simulating) the x86 language
>>>>>>>>>>> finite string of DDD including emulating the finite string of
>>>>>>>>>>> itself emulating the finite string of DDD up until the point
>>>>>>>>>>> where the emulated emulated DDD would call HHH(DDD) again.
>>>>>>>>>> Whereupon the simulated HHH would abort, if it weren't
>>>>>>>>>> unnecessarily aborted.
>>>>>>>>> If the first HHH to meet its abort criteria does not act on this
>>>>>>>>> criteria then none of them do.
>>>>>>>> And if the first one does, all of them do.
>>>>>>> In theory this seems true when ignoring or failing to comprehend
>>>>>>> key details.
>>>>>> In practice you programmed H impurely.
>>>>> Which totally does not matter to the slightest degree when you have
>>>>> the discipline to stay within the precisely designated scope of the
>>>>> exact words that I am saying.
>>>>> When HHH is an x86 emulation based termination analyzer then each
>>>>> DDD *correctly_emulated_by* any HHH that it calls cannot possibly
>>>>> return no matter what this HHH does.
>>>> Exactly, because your nested HHHs do not abort.
>>> In other words you continue to fail to understand that unless the
>>> first one aborts then none of them can possibly abort because they all
>>> have the exact same code.
>> Then HHH should report itself as halting, when they would all abort.
> They would not all abort when you pay close attention to ALL of the
> details. It is utterly impossible for any of them besides the outermost
> one to abort because it aborts before any of the rest of them see their
> abort criteria has been met.
Only because they aren't simulated. But they are still terminating
programs. An infinite loop is still non-halting even if I never run it.

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.