Path: ...!eternal-september.org!feeder3.eternal-september.org!news.quux.org!news.nk.ca!rocksolid2!i2pn2.org!.POSTED!not-for-mail
From: Richard Damon <richard@damon-family.org>
Newsgroups: sci.logic
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
 (extra-ordinary)
Date: Thu, 28 Nov 2024 08:01:52 -0500
Organization: i2pn2 (i2pn.org)
Message-ID: <659cb7a16573c854e96c7a982fe8b15397fb1210@i2pn2.org>
References: <31419fde-62b3-46f3-89f6-a48f1fe82bc0@att.net>
 <vhkhun$28qt$1@dont-email.me> <vhmtph$j1ek$1@dont-email.me>
 <vhn1jk$jf6v$1@dont-email.me> <vhn3po$jvo1$1@dont-email.me>
 <vhn420$jf6v$3@dont-email.me> <vhpg51$13soc$1@dont-email.me>
 <vhpnrb$15239$1@dont-email.me> <vhs2gn$1kjtc$1@dont-email.me>
 <vhs4ue$1ku9t$1@dont-email.me> <vhv6or$280s6$1@dont-email.me>
 <vhvbjb$28n6o$1@dont-email.me> <vi1dbj$2moon$1@dont-email.me>
 <vi224l$2pgrd$1@dont-email.me> <vi4383$3csd4$2@dont-email.me>
 <vi4a6c$3dt4s$2@dont-email.me>
 <c5a03e73203e6409f6b50c25b84a22d8df0d210b@i2pn2.org>
 <vi4k5a$3fj1t$1@dont-email.me>
 <8b860c66587b6d5d18e565caddb42cc3d5bb813c@i2pn2.org>
 <vi4vg4$3hg8t$3@dont-email.me> <vi509b$3hqcp$1@dont-email.me>
 <vi56el$3is82$1@dont-email.me> <vi57p2$3j62u$1@dont-email.me>
 <vi6tu2$3v0dn$3@dont-email.me>
 <bedba0f79694c3adbbcb4eff22a28b9597ea1293@i2pn2.org>
 <vi7uam$5cmb$1@dont-email.me>
 <376546bee4809e20528e0e9481315611ec5c3848@i2pn2.org>
 <vi9n75$hepc$1@dont-email.me>
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8; format=flowed
Content-Transfer-Encoding: 7bit
Injection-Date: Thu, 28 Nov 2024 13:01:52 -0000 (UTC)
Injection-Info: i2pn2.org;
	logging-data="312723"; mail-complaints-to="usenet@i2pn2.org";
	posting-account="diqKR1lalukngNWEqoq9/uFtbkm5U+w3w6FQ0yesrXg";
User-Agent: Mozilla Thunderbird
X-Spam-Checker-Version: SpamAssassin 4.0.0
Content-Language: en-US
In-Reply-To: <vi9n75$hepc$1@dont-email.me>
Bytes: 2801
Lines: 22

On 11/28/24 7:20 AM, WM wrote:
> On 27.11.2024 22:20, Richard Damon wrote:
>> On 11/27/24 3:09 PM, WM wrote:
> 
>>> It is completed! Every number 10n starts wit a black hat.
>>
>> Right, and it gives that hat to n, so every number gets one.
>>
>> And, 10n will get back a hat from 100n, so it still have one at the end.
>>
> It seems so, but that is impossible. Up to every 10n, the interval 1, 2, 
> 3, ... 10n has a covering of 1/10 only. The limit of this sequence is 
> 1/10 too. And since this is true for all natural numbers, where should 
> additional hats come from?
> 
> Regards, WM
> 

No, it is possilbe, but beyond your understanding, because you refuse to 
actually work with the infinite set, and think a finite set is an 
adiquite model for the inifinite.

Sorry, you are just proving your incompetence.