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Date: Wed, 12 Jun 2024 00:20:54 -0400
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On 6/12/2024 12:05 AM, bitrex wrote:

> even and odd parts in (4), I think plugging that form into 
> tanh(arctan(z)) = (e^z - e^-z) / (e^z + e^-z)

tanh(arctan(z)) = [e^(arctan(z)) - e^(-arctan(z))]/[e^(arctan(z)) + 
e^(-arctan(z))], rather.