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Path: ...!feeds.phibee-telecom.net!news.mixmin.net!feeder1-2.proxad.net!proxad.net!feeder1-1.proxad.net!cleanfeed2-b.proxad.net!nnrp4-2.free.fr!not-for-mail Newsgroups: sci.physics.relativity Subject: Re: Einstein's Mistakes From: nospam@de-ster.demon.nl (J. J. Lodder) Reply-To: jjlxa31@xs4all.nl (J. J. Lodder) Date: Thu, 24 Oct 2024 23:42:00 +0200 References: <8110cafcb23c6f0f60d6414719aba934@www.novabbs.com> <e3e193c97e0d6ada80d10cd3c32a33f1@www.novabbs.com> <3845371e152b2a983d5023e601cd1c12@www.novabbs.com> <374914495b8f592bcb19b2cfb0dce968@www.novabbs.com> <67d1b2c24f289b892604895a401fbe86@www.novabbs.com> <61b46394e14345f28a4a1615ddddd374@www.novabbs.com> <vf86c7$1fueh$1@dont-email.me> <a2485088f7b96dd773e014a8809ff97b@www.novabbs.com> <x_xSO.2461785$VK2e.487693@fx01.ams4> Organization: De Ster Mail-Copies-To: nobody User-Agent: MacSOUP/2.8.5 (ea919cf118) (Mac OS 10.12.6) Lines: 101 Message-ID: <671abf29$0$525$426a34cc@news.free.fr> NNTP-Posting-Date: 24 Oct 2024 23:42:01 CEST NNTP-Posting-Host: 213.10.137.58 X-Trace: 1729806121 news-4.free.fr 525 213.10.137.58:58124 X-Complaints-To: abuse@proxad.net Bytes: 5193 Paul B. Andersen <relativity@paulba.no> wrote: > Den 23.10.2024 18:38, skrev rhertz: > > On Tue, 22 Oct 2024 12:41:19 +0000, Paul.B.Andersen wrote: > >> > >> Of course there are Coulomb forces that accelerate the parts of > >> the atom in a fission. > > This is not disputed! > > So why do you act as it is? > > >> > >> And you know that this _confirms_ E = mc? because: > > we know: > > >> Generally: > >> In a fission the mass of the constituents is less than > >> the mass of the fissioned atom. > >> ------------------ > >> > >> All physicists knew that in 1939, obviously. > >> > >> https://www.atomicarchive.com/resources/documents/beginnings/nature_meitner ..html > >> Quote: > >> "It seems therefore possible that the uranium nucleus has only small > >> stability of form, and may, after neutron capture, divide itself > >> into two nuclei of roughly equal size (the precise ratio of sizes > >> depending on finer structural features and perhaps partly on chance). > >> These two nuclei will repel each other and should gain a total kinetic > >> energy of c. 200 Mev., as calculated from nuclear radius and charge." > >> > >> Meitner calculated from the electrostatic repulsion that > >> the kinetic energy of the constituents would be ca 200 Mev. > > Because this was the simplest way to estimate the released energy. > > >> > >> Quote: > >> "This amount of energy may actually be expected to be available > >> from the difference in packing fraction between uranium and the > >> elements in the middle of the periodic system." > >> > >> When Meitner found that this mass difference was equivalent to > >> ca.200 Mev it could only be through E = mc?. > > So Meitner, like all physicists, took E = mc? for granted. > > >> > >> You know this, because I told you 5 years ago. > >> > >> So why do you pretend to be ignorant of the fact that all physicists > >> (and chemists) at the time took E = mc? for granted? > > > > > > > These are excerpts from Serber's 1992, "Los Alamos Primer": > > > > > > Somehow the popular notion took hold long ago that Einstein's theory of > > relativity, in particular his famous equation E = mc?, plays some > > essential role in the theory of fission. Albert Einstein had a part in > > alerting the United States government to the possibility of building an > > atomic bomb, but his theory of relativity is not required in discussing > > fission. The theory of fission is what physicists call a nonrelativistic > > theory, meaning that relativistic effects are too small to affect the > > dynamics of the fission process significantly. > > Section 2 of the Primer gives a more exact calculation of the ratio of > > the > > energy released by the fission of a gram of uranium to the energy > > released by the explosion of a gram of TNT. > > Even if the atom bomb could have been made without E = mc?, > the statement above shows that Serber, as all physicists, > knew E = mc?, they all took it for granted. > > Serber doesn't say that E = mc? is not a valid theory, > he says that E = mc? wasn't much help in making the atom bomb. > > So I ask you again: > Why do you pretend to be ignorant of the fact that all physicists > (and chemists) at the time took E = mc? for granted? It's hopeless. RH is completely clueless when it comes to real physics. (and he is unwilling to learn) > E = mc? is now thoroughly experimentally verified, and the atom bomb > is part of the experimental evidence. Of course, but not really needed. Mass spectroscopy was invented by J. J. Thomson in 1913, and refined by his student, F. W. Aston. (discovering lots of isotopes) In 1932, Kenneth Bainbridge pushed the accuracy of it to about 10^-4, which was good enough to verify E = mc^2 directly, for atomic nuclei. So the mass excess of the Uranium nucleus of about 200 MeV was well known to 'everybody', well before WWII got started, Jan