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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: Functions computed by Turing Machines MUST apply finite string
 transformations to inputs --- MT
Date: Wed, 7 May 2025 15:44:41 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
Message-ID: <6c627041e7df24bb64442ad7e0ee03db6a74aab6@i2pn2.org>
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Am Wed, 07 May 2025 10:03:55 -0500 schrieb olcott:
> On 5/7/2025 7:01 AM, dbush wrote:
>> On 5/7/2025 6:16 AM, Fred. Zwarts wrote:
>>> Op 06.mei.2025 om 21:15 schreef olcott:

>>>> None-the-less it is the words that the best selling author of theory
>>>> of computation textbooks agreed to: *would never stop running unless
>>>> aborted*
>>>> is the hypothetical HHH/DD pair where the same HHH that DD calls does
>>>> not abort the simulation of its input.
>>>>
>>> Nevertheless, this change makes it fundamentally different.
>>> I can't believe that you are so stupid to think that modifying a
>>> program does not make a program different. Are you trolling?
>> 
>> Given that he's shown he doesn't understand (and this list is by no
>> means exhaustive):
>> * what requirements are * what correct means * what true means * what a
>> proof is * how proof by contradiction works
>> I wouldn't put it past him that he actually believes it.  He'll say
>> anything to avoid admitting to himself that he wasted that last 22
>> years not understanding what he was working on.
>> (Anyone else that wants to add to this list, feel free)
> 
> A simulating halt decider must correctly predict *what the behavior
> would be* if it did not abort its simulation.
....if it, the simulator, didn't abort. The input DD that is being
simulated still calls the same real HHH that does abort.

>      *simulated D would never stop running unless aborted*
>       means that HHH examines what the behavior of DD *would be*
>       if it never aborted its simulation. This is a different
>       hypothetical HHH/DD pair than the actual HHH/DD pair.
So a non-input.

> If it did not do this and simply kept simulating a non-terminating input
> it would break the requirement that itself must halt.
If it does do this it breaks the requirement that it must return the value
of a full simulation.

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.