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Path: ...!weretis.net!feeder9.news.weretis.net!news.quux.org!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail From: john larkin <jl@glen--canyon.com> Newsgroups: sci.electronics.design Subject: Re: 50 ohm termination Date: Mon, 17 Mar 2025 16:33:03 -0700 Organization: A noiseless patient Spider Lines: 26 Message-ID: <6nbhtjlhlpmqkscehm9nn6mfmuvkai55lo@4ax.com> References: <20250317190219.00001b76@dne3.net> MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit Injection-Date: Tue, 18 Mar 2025 00:27:31 +0100 (CET) Injection-Info: dont-email.me; posting-host="924b4f5e5b40f5fbafe25c9395895cd0"; logging-data="1244829"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1+H/wEMcIfcg+/MJ7Dy+Wrb" User-Agent: ForteAgent/8.00.32.1272 Cancel-Lock: sha1:nypaRTGjqZtuiKopa/Bw0PYT7B8= Bytes: 1873 On Mon, 17 Mar 2025 19:02:19 -0400, Toaster <toaster@dne3.net> wrote: >Can I get away with terminating the far end of a transmission line or >do I need a series resistor at the source and a parallel resistor at >the destination? > >Thank you, >Toaster You can get clean wideband transmission with any impedance at the source and a 50 ohm termination at the end. Voltages will be the same all along the line. Assuming theoretical lossless trans lines of course. You can also source terminate, namely drive a 50 ohm line from a 50 ohm source. The signal at the end of the line, unterminated, will be identical to the source internal voltage. But intermediate points will be awful. For extreme cases, terminate both ends at 50 ohms. That will minimize reflections caused by imperfect connectors or terminators. It wastes a lot of power. You can Spice all this.