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Subject: Re: Sync two clocks
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From: Richard Hachel <r.hachel@tiscali.fr>
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Le 24/08/2024 à 12:08, "Paul.B.Andersen" a écrit :
> Den 23.08.2024 13:30, skrev Richard Hachel:
>> Le 23/08/2024 à 10:55, Mikko a écrit :
>>> On 2024-08-23 05:41:50 +0000, Thomas Heger said:
>>> 
>>>> Am Mittwoch000021, 21.08.2024 um 20:42 schrieb Paul.B.Andersen:
>>>>>
>>>>> Richard, read your watch NOW. Write down the time nn:nn:nn.
>>>>> The time nn:nn:nn is a proper time (read off a clock), it is
>>>>> invariant, not depending on frame of reference.
>>>>>
>>>>> Nobody can have another opinion of what time YOU read of YOUR watch.
>>>>
>>>> This is not, what 'invariant' means in the context of relativity.
>>> 
>>> Yes, it is.
>>> 
>>>> Meant is, that time would not change, if you switch from one frame of 
>>>> reference to another.
>>> 
>>> No, it means that whatever is called "invariant" is the same for all
>>> frames. In the current case, the number wirtten on the paper is invariant.
>>> 
>>> Mikko
>> 
>> Here is yet another proof of what I am saying, and of the need to 
>> re-explain things correctly.
> 
> Do you mean that the fact that Tomas Heger doesn't know what
> "invariant" means, is a proof of the need to re-explain
> my statement correctly?
> 
> My statement was:
> " Richard, read your watch NOW. Write down the time nn:nn:nn.
>    The time nn:nn:nn is a proper time (read off a clock), it is
>    invariant, not depending on frame of reference.
>    Nobody can have another opinion of what time YOU read of YOUR watch."
> 
> Both "proper time" and "invariant" are explained in the text.
> 
> Exactly what do you not understand?
> What is needed to be re-explained correctly?

What you say is quite obvious, and that is not the problem.
We all say, even the buffoon Python, that when the event e1 occurs (A 
beeps), A starts his watch.
At A, we note tA(e1)=0
e2 is the capture of the beep by B...
e3 is the event that characterizes the return of the signal to A.
We note tA(e3)=2
We know that AB=3.10^8m/s
This leads to tA(e3)-tA(e1)=2AB/c
Everyone agrees on this, and everyone always has, even the fiercest 
Newtonians, or the fiercest relativists.
Fighting over this is particularly stupid.
We continue:
Everyone also agrees, and I too, that tA(e1)=0 is an invariant for all 
observers in the universe, whatever their position, whatever their speed, 
whatever their acceleration.
As everyone agrees that if A takes a picture of his dog Rintintin, at this 
precise moment, then broadcasts it to the entire universe, the entire 
universe will receive a picture of his dog, and not a picture of a 
rhinoceros in Africa.
The opposite would be absurd.

That's what I say, and I see with sadness (don't laugh friends), that my 
intelligence seems to surpass the entire scientific community, and that 
for having taken, what I say is distorted.
That's particularly stupid, and perfectly contradictory with
the claim of being a good fan of the theory of relativity.

R.H.