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From: Richard Damon <richard@damon-family.org>
Newsgroups: sci.math
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
 (extra-ordinary)
Date: Fri, 17 Jan 2025 09:52:30 -0500
Organization: i2pn2 (i2pn.org)
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On 1/17/25 5:58 AM, WM wrote:
> On 17.01.2025 01:56, Jim Burns wrote:
>> On 1/16/2025 8:32 AM, WM wrote:
> 
>>>> A potentiallyᵂᴹ infiniteˢᵉᵗ set
>>>> has all available places occupied,
>>>
>>> But it can grow.
>>
>> No, it can't.
> 
> Mimicking Damon?
> 
> "Potential infinity refers to a procedure that gets closer and closer 
> to, but never quite reaches, an infinite end. For instance, the sequence 
> of numbers 1, 2, 3, 4, ... gets higher and higher, but it has no end; it 
> never gets to infinity.[...]
>      Completed infinity, or actual infinity, is an infinity that one 
> actually reaches; the process is already done. For instance, let's put 
> braces around that sequence mentioned earlier: {1, 2, 3, 4, ...}. With 
> this notation, we are indicating the set of all positive integers." [E. 
> Schechter: "Potential versus completed infinity: Its history and 
> controversy" (5 Dec 2009)]
> 
> Note: "With this notation, we are indicating the set of all positive 
> integers." That implies, with the other notion we are not.


Nope, *YOU* don't understand the terminology.

>>
>>> Multiplying all its elements by 2
>>> creates new elements.
>>
>> No. it doesn't.
> 
> If all are there and all are doubled, then greater elements are 
> produced. This is the mathematics of 2n > n. That you cannot accept it, 
> shows that your set theory contradicts mathematics.

Nope, because they were already there. That is the nature of INFINITY.

Something your tiny brain can't comprend.

>>
>>>> the same as any other set,
>>>> which is to say,
>>>> it is (has been, will be) completeᵂᴹ.
>>>
>>> Then new numbers must be outside.
>>
>> There are no new numbers.
> 
> 2n > n proves new  and greater numbers than are doubled.

Nope, it doesn't, your mentioning it just proves you don't understand 
what infinity means.

>>
>> A step is never from finite to infinite.
>> Therefore, a step never crosses ω
> 
> Therefore no ω does exist. That is the only alternative. Potential 
> infinity.

Maybe in YOUR logic, you can't get to omega, because your logic can't 
handle infinity.

That doesn't mean that it can't exist in better logic systems.

That you claim otherwise just proves your stupidity, and that it is so 
great you can't see your own stupidity.

> 
> Regards, WM