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Path: news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail From: Ben Bacarisse <ben@bsb.me.uk> Newsgroups: comp.theory Subject: Re: Analysis of =?utf-8?Q?Flibble=E2=80=99s?= Latest: Detecting vs. Simulating Infinite Recursion ZFC Date: Fri, 23 May 2025 14:00:35 +0100 Organization: A noiseless patient Spider Lines: 71 Message-ID: <87a573xz0s.fsf@bsb.me.uk> References: <Ms4XP.801347$BFJ.668081@fx13.ams4> <100jpv9$2m0ln$4@dont-email.me> <100kt0c$2tae8$3@dont-email.me> <100ktr7$2reaa$1@dont-email.me> <100l09v$2tae8$5@dont-email.me> <100l1ov$2ul3j$1@dont-email.me> <100l3jh$2v0e9$1@dont-email.me> <100l5c8$2ul3j$2@dont-email.me> <100l75g$2vpq3$1@dont-email.me> <100l887$2ul3i$2@dont-email.me> <100l9gh$30aak$1@dont-email.me> <100lc4o$30pgm$1@dont-email.me> <100ld1u$312c9$1@dont-email.me> <100lg4g$31jt3$1@dont-email.me> <100lkdv$32ib3$1@dont-email.me> <100lmif$32v06$1@dont-email.me> <100lmp3$32ven$1@dont-email.me> <100m319$38k55$2@dont-email.me> <87jz69xlpx.fsf@nosuchdomain.example.com> <100mder$39slu$2@dont-email.me> <100oipb$3oge1$1@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain Injection-Date: Fri, 23 May 2025 15:00:35 +0200 (CEST) Injection-Info: dont-email.me; posting-host="5f842c4fba7e64780966dc59bd931b69"; logging-data="105056"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1/D4gNvLGa9/hwbS5RntgDTDxIB7V+BppM=" User-Agent: Gnus/5.13 (Gnus v5.13) Cancel-Lock: sha1:aDOPbQnDLlBe+AmNVKYdA2EFJNk= sha1:8VMkvSasXO/bhqLt5N1dI93gcRw= X-BSB-Auth: 1.ffd0476de149a4b266ea.20250523140035BST.87a573xz0s.fsf@bsb.me.uk Mike Terry <news.dead.person.stones@darjeeling.plus.com> writes: > On 22/05/2025 06:41, Richard Heathfield wrote: >> On 22/05/2025 06:23, Keith Thompson wrote: >>> Richard Heathfield <rjh@cpax.org.uk> writes: >>>> On 22/05/2025 00:14, olcott wrote: >>>>> On 5/21/2025 6:11 PM, Richard Heathfield wrote: >>> [...] >>>>>> Turing proved that what you're asking is impossible. >>>>>> >>>>> That is not what he proved. >>>> >>>> Then you'll be able to write a universal termination analyser that can >>>> correctly report for any program and any input whether it halts. Good >>>> luck with that. >>> >>> Not necessarily. >> Of course not. But I'm just reflecting. He seemed to think that my >> inability to write the kind of program Turing envisaged (an inability >> that I readily concede) is evidence for his argument. Well, what's sauce >> for the goose is sauce for the gander. >> >>> Even if olcott had refuted the proofs of the >>> insolvability of the Halting Problem -- or even if he had proved >>> that a universal halt decider is possible >> And we both know what we both think of that idea. >> >>> -- that doesn't imply >>> that he or anyone else would be able to write one. >> Indeed. >> >>> I've never been entirely clear on what olcott is claiming. >> Nor I. Mike Terry seems to have a pretty good handle on it, but no matter >> how clearly he explains it to me my eyes glaze over and I start to snore. > > Hey, it's the way I tell 'em! > > Here's what the tabloids might have said about it, if it had made the > front pages when the story broke: > > COMPUTER BOFFIN IS TURING IN HIS GRAVE! > > An Internet crank claims to have refuted Linz HP proof by creating a > Halt Decider that CORRECTLY decides its own "impossible input"! > The computing world is underwhelmed. > > Better? (Appologies for the headline, it's the best I could come up > with.) And the big picture is that this can be done because false is the correct halting decision for some halting computations. He has said this explicitly (as I have posted before) but he has also explained it in words: | When-so-ever a halt decider correctly determines that its input would | never halt unless forced to halt by this halt decider this halt | decider has made a correct not-halting determination. Or perhaps you prefer this explanation from 2023: | (1) A return value of 1 from H(D,D) means the input to H(D,D) has halted | | (2) A return value of 0 from H(D,D) has been redefined to mean | (a) D does not halt | (b) D has been defined to do the opposite of whatever Boolean value | that H returns. All very clear. Of course (2)(b) is undeciable in general. -- Ben.