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From: Keith Thompson <Keith.S.Thompson+u@gmail.com>
Newsgroups: comp.lang.c
Subject: Re: Top 10 most common hard skills listed on resumes...
Date: Sat, 31 Aug 2024 15:31:29 -0700
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Bart <bc@freeuk.com> writes:
[...]
> Given this:
>
>    x + y = z;
>    (x + y) = z;
>
> My compiler produces the same AST for the LHS of '=' in both cases.
[...]

If that's the case (and I don't doubt that it is), then your compiler is
not following the grammar specified by the ISO C standard.  Since
`x + y` is not a unary-expression, `x + y = z` is not a syntactically
valid assignment expression.

A parser that strictly follows the ISO C grammar would reject
(diagnose, flag, whatever) `x + y = z;` just as it would reject `x = y +;`.

This is an observation, not a complaint.  It doesn't imply that your
compiler is non-conforming or buggy.  A parser that doesn't strictly
follow the ISO C grammar could still be part of a conforming compiler.

-- 
Keith Thompson (The_Other_Keith) Keith.S.Thompson+u@gmail.com
void Void(void) { Void(); } /* The recursive call of the void */