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From: Richard Damon <richard@damon-family.org>
Newsgroups: sci.math
Subject: Re: How many different unit fractions are lessorequal than all unit
 fractions?
Date: Sat, 28 Sep 2024 07:12:27 -0400
Organization: i2pn2 (i2pn.org)
Message-ID: <90348169ab3b4b500ddb2d0c339504fe5c57fa4b@i2pn2.org>
References: <vb4rde$22fb4$2@solani.org> <vc2gfb$130uk$1@dont-email.me>
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 <vcehl6$2boc$3@dont-email.me> <f1d14b16-2c12-4cfb-b7f5-c58cc5724f94@att.net>
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 <vcn8n8$1nfqa$1@dont-email.me> <283c426f-ab1c-4ef0-a06c-1bf7d28a2cfa@att.net>
 <vcpo5e$29qe5$1@dont-email.me> <6b50a171-8127-4ce6-9bd3-2dc213638e9b@att.net>
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On 9/27/24 2:42 PM, WM wrote:
> On 25.09.2024 18:39, joes wrote:
>> Am Wed, 25 Sep 2024 17:51:56 +0200 schrieb WM:
> 
>>> NUF(x) distinguishes all points.
>> How does it distinguish dark points?
> 
> By our mathematical knowledge about ∀n ∈ ℕ: 1/n - 1/(n+1) > 0


Which means for any 1/n, there exist a 1/(n+1) that is smaller than it, 
and thus there is no smallest 1/n.

> 
>>> NUF increases. At no point it can increase by more than 1.
>> Right, and there is no point "next to" 0
> 
> There is a unit fraction next to 0.

Nope. "Next To" isn't a property of that set.

> 
>>> Even if most mathematicians are far too stupid to understand this, I
>>> will repeat it on and on, maybe that sometime some will get it.
>> You should try explaining it a different way.
> 
> ∀n ∈ ℕ: 1/n - 1/(n+1) > 0
> is invincible.

Right, and thus, for *ANY* 1/n, there exist a 1/(n+1) that will be 
smaller than it.

PERIOD.

Since, one property of ℕ is that ∀n ∈ ℕ, the value n+1 exists, and
(n+1) ∈ ℕ

You ignore this FACT because it proves your wrong, showing that you are 
nothing but a STUPID LIAR.

> 
> Regards, WM
> 
>