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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: ChatGPT refutes the key rebuttal of my work
Date: Wed, 16 Oct 2024 20:02:41 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
Message-ID: <92373359ad257199f3190fc4ecf935bbc4d3017a@i2pn2.org>
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Am Wed, 16 Oct 2024 14:39:37 -0500 schrieb olcott:
> On 10/16/2024 2:33 PM, joes wrote:
>> Am Wed, 16 Oct 2024 13:59:58 -0500 schrieb olcott:
>>> On 10/16/2024 1:47 PM, joes wrote:
>>>> Am Wed, 16 Oct 2024 13:35:01 -0500 schrieb olcott:
>>>>> On 10/16/2024 1:06 PM, joes wrote:
>>>>>> Am Wed, 16 Oct 2024 12:46:01 -0500 schrieb olcott:
>>>>>>> On 10/16/2024 12:27 PM, joes wrote:
>>>>>>>> Am Wed, 16 Oct 2024 10:39:21 -0500 schrieb olcott:
>>>>>>>>> On 10/16/2024 9:45 AM, joes wrote:
>>>>>>>>>> Am Wed, 16 Oct 2024 09:11:22 -0500 schrieb olcott:
>>>>>>>>>>> On 10/16/2024 9:01 AM, joes wrote:
>>>>>>>>>>>> Am Wed, 16 Oct 2024 08:31:43 -0500 schrieb olcott:
>>>>>>>>>>>>> On 10/16/2024 1:33 AM, joes wrote:
>>>>
>>>>>>>>>>>>> Terminating C functions must reach their "return" statement.
>>>>>>>>>>>> Which DDD does.
>>>>>>>>>>> THIS IS ALSO THE INDUSTRY STANDARD DEFINITION It is stipulated
>>>>>>>>>>> that *correct_x86_emulation* means that a finite string of x86
>>>>>>>>>>> instructions is emulated according to the semantics of the x86
>>>>>>>>>>> language beginning with the first bytes of this string.
>>>>>>>>>> You are not simulating the given program, but a version that
>>>>>>>>>> differs in the abort check.
>>>>>>>>> HHH is correctly emulating (not simulating) the x86 language
>>>>>>>>> finite string of DDD including emulating the finite string of
>>>>>>>>> itself emulating the finite string of DDD up until the point
>>>>>>>>> where the emulated emulated DDD would call HHH(DDD) again.
>>>>>>>> Whereupon the simulated HHH would abort, if it weren't
>>>>>>>> unnecessarily aborted.
>>>>>>> If the first HHH to meet its abort criteria does not act on this
>>>>>>> criteria then none of them do.
>>>>>> And if the first one does, all of them do.
>>>>> In theory this seems true when ignoring or failing to comprehend key
>>>>> details.
>>>> In practice you programmed H impurely.
>>> Which totally does not matter to the slightest degree when you have
>>> the discipline to stay within the precisely designated scope of the
>>> exact words that I am saying.
>>> When HHH is an x86 emulation based termination analyzer then each DDD
>>> *correctly_emulated_by* any HHH that it calls cannot possibly return
>>> no matter what this HHH does.
>> Exactly, because your nested HHHs do not abort.
> In other words you continue to fail to understand that unless the first
> one aborts then none of them can possibly abort because they all have
> the exact same code.
Then HHH should report itself as halting, when they would all abort.

>>>>>>>>>>> When HHH is an x86 emulation based termination analyzer then
>>>>>>>>>>> each DDD *correctly_emulated_by* any HHH that it calls never
>>>>>>>>>>> returns.
>>>>>>>>>> It is not a correct emulation if it has a different termination
>>>>>>>>>> status.
-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.