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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: Any honest person that knows the x86 language can see... predict
 correctly
Date: Wed, 31 Jul 2024 08:54:32 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Tue, 30 Jul 2024 16:13:55 -0500 schrieb olcott:
> On 7/30/2024 4:07 PM, joes wrote:
>> Am Tue, 30 Jul 2024 15:05:54 -0500 schrieb olcott:
>>> On 7/30/2024 1:48 PM, Fred. Zwarts wrote:
>>>> Op 30.jul.2024 om 17:14 schreef olcott:
>>>>> On 7/30/2024 9:51 AM, Fred. Zwarts wrote:
>>>>>> Op 30.jul.2024 om 16:21 schreef olcott:
>>>>>>> On 7/30/2024 1:52 AM, Mikko wrote:
>>>>>>>> On 2024-07-29 14:07:53 +0000, olcott said:

>>> I proved otherwise. When the abort code is commented out then it keeps
>>> repeating again and again, thus conclusively proving that is must be
>>> aborted or HHH never halts.
>> But the abort is not commented out in the running code!
> I modified the original code by commenting out the abort and it does
> endlessly repeat just like HHH correctly predicted.
Yes, and that modification makes HHH not call itself but a different
program. You'd need to also comment out the outermost abort; then it
wouldn't halt, but if you change HHH to abort, you change all copies
of it at the same time (to keep the recursive call structure).

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.