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From: joes <noreply@example.org>
Newsgroups: sci.math
Subject: Re: 2N=E
Date: Tue, 22 Oct 2024 09:43:29 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
Message-ID: <9e98e573c0368690d336299ab78121c3240aa8e7@i2pn2.org>
References: <vb4rde$22fb4$2@solani.org> <vejte9$e3ds$1@solani.org>
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Am Mon, 21 Oct 2024 20:35:59 +0200 schrieb WM:
> On 21.10.2024 14:41, joes wrote:
>> Am Mon, 21 Oct 2024 11:59:00 +0200 schrieb WM:
>>> On 21.10.2024 10:21, joes wrote:
>>>> Am Mon, 21 Oct 2024 10:14:07 +0200 schrieb WM:
>>>
>>>>> If the range was complete, the image shows that the range was not
>>>>> complete.
>>>> If the range really is complete, it needs to be infinite, so it can
>>>> include the larger numbers.
>>> No. No set of numbers can include larger numbers.
>> An infinite set can contain an m>n for every n in it.
> Yes, but all the numbers which the set contains are either complete and
> fixed, or they are variable such that with each request larger numbers
> can be creazed.
"yes, but actually no" The numbers ARE fixed, there are just inf. many
of them.  The larger numbers have already all been "created".

> The latter case is called potential infinity. In case they are complete
> and fixed we can multiply them by 2 and find larger numbers.
-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.