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From: Jacques Mathon <mathon.jacques@free.fr>
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Le 06/06/2023 à 08:08, robby a écrit :
> Le 05/06/2023 à 23:02, Michel Talon a écrit :
>> Tu veux dire 10 doit diviser x,
> 
> yep.

? ? ?

>> et encore c'est pas garanti.
> 
> qu'est-ce que j'ai raté ? il peut y avoir un diviseur commun à X et X-1 ?

Voyons voir l'éventuel trou dans la raquette.
Tu écrivais :
y = 1/ ( 1/10 - 1/x ) =  10x / ( x - 10  )

OK !

donc x >= 10 et x doit diviser 10

Peut-être ici ?
Je vois juste que X-10 doit diviser 10X

Ce qui est bien le cas pour 14 (ainsi que pour 11,12,15 et 20)

Amicalement
-- 
Jacques