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Le 25/06/2024 à 13:47, efji a écrit :
> Le 25/06/2024 à 13:36, Richard Hachel a écrit :

> Et le gros malin il fait comment pour résoudre
> 
> sqrt(3x+7)+sqrt(x+2)=2

 Faaaaacile!

 sqrt(3x+7)=2-sqrt(x-2)

 3x+7=[2-sqrt(x+2)]²

 3x+7=4-4sqrt(x+2)+(x+2)

 2x+1=-4sqrt(x+2)

 4x²+4x+1=16x+32

 4x²-12x-31=0

 Deux racines x'=-2.6622775   x"=4.6622775

 Seule le première racine est compatible avec x<-2

R.H.