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From: Python <jp@python.invalid>

Le 20/05/2025 à 15:00, Michel Talon a écrit :
>>> 5) toujours en vertu de la même règle :
>>> exp(4iπ)^(1/2) = exp(2iπ) = +1
>> 
>> Même réponse que 4.

Pour clarifier : exp(2iπ) = 1 mais exp(4iπ)^(1/2) a deux valeur car 
z->z^(1/2) est multivaluée, et l'une de ces valeurs est bien 1.