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Subject: Re: Understanding the theory of special relativity
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Date: Thu, 23 Jan 25 09:45:34 +0000
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From: Richard Hachel <r.hachel@liscati.fr.invalid>
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Le 22/01/2025 à 22:11, "Paul.B.Andersen" a écrit :
> Den 21.01.2025 17:51, skrev Richard Hachel:
> =========================================
> There is no reciprocity in this scenario.
> =========================================
> 
> After the journey Stella's clock shows 10 (9) years while
> Terrence clock shows 23.9 (13.5) years.
> PERIOD.
> 
> How can you call this reciprocal?
> 
>> 
>> Paul, Paul, you do not understand anything at all of what I am saying, 
>> and instead of trying to understand, you take the theory as a joke.
> 
> A very bad joke. Not funny at all. I don't laugh.
> 
> Case closed.

There is a flaw in your way of understanding the ratio of observable time 
(terrestrial) and proper time (rockets in general).
As much in Galilean environments, where you only involve the reciprocal 
internal mechanism of watches, as in accelerated frames of reference, 
where you confuse the progression of observable times (red line) with the 
rotating path on a drawing (blue line) of the end of the segment To.
This results in a lower Tr/To ratio and an incorrect and too low predicted 
Tr (tau). All physicists do this, but it is wrong.
The correct equation is however very simple, and there is not even any 
need to go through an integration (I do not use one, as I do not use the 
invariance of the space-time interval or the Minkowski block, which bring 
more misunderstandings than practical solutions).

The correct equation is To(observable time reference Earth) with 
To=Tr.sqrt(1+(1/4)Vr²/c²) where Vr is the real speed of the object at a 
given time.

We can then write:
To=Tr.sqrt(1+(1/4)a².Tr²/c²)

I'll let you do the math, you'll see that my To is slightly lower than 
yours, and conversely if you have To and you look for Tr, you will have a 
higher rate than expected by your calculation.

Je rappelle que ce qui est réciproque, toujours, seconde après seconde, 
c'est la chronotropie interne des montres. Toujours, l'autre montre bat 
plus lentement en son mécanisme interne, et toujours, toujours, toujours 
: To=Tr/sqrt(1-Vo²/c²) où Vo est la vitesse relative instantanée à 
chaque instant. 

MAIS il faut prendre en compte les problémes :
1) d'anisochronie (traverser de l'espace, c'est traverser AUSSI du temps, 
car la simultanéité est relative an fonction de l'endroit de l'espace 
où l'on se trouve)
2) d'effet-zoom spatial énorme (l'espace est un mollusque de 
référence). Je le répète, même si ça rend fou tout le monde : 
lorsque Terrence voit Stella virer, et revenir sur lui, rien ne se passe. 
Il la voit, évidemment, à 12 ly. Le contraire serait absurde. 
Mais Stella voit Terrence à 36ly!!!
C'est là la dernière et la plus formidable clé de l'explication du 
voyageur de Langevin. Explication que je donne depuis des années, et qui 
fait rire tout le monde, parce que personne ne comprend cette géométrie 
magnifique de l'espace et du temps. 

R.H.