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NNTP-Posting-Date: Mon, 30 Dec 2024 01:17:51 +0000
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
 (extra-ordinary)
Newsgroups: sci.math
References: <vg7cp8$9jka$1@dont-email.me> <vjjg6p$3tvsg$1@dont-email.me>
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From: Ross Finlayson <ross.a.finlayson@gmail.com>
Date: Sun, 29 Dec 2024 17:17:45 -0800
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On 12/29/2024 01:48 PM, Jim Burns wrote:
> On 12/29/2024 3:57 PM, Ross Finlayson wrote:
>> On 12/29/2024 12:34 PM, Jim Burns wrote:
>>> On 12/29/2024 1:15 PM, Ross Finlayson wrote:
>>>> On 12/29/2024 06:43 AM, joes wrote:
>
>>>>> The infinite union doesn’t.
>>>>
>>>> There is no "infinite union" in ZF,
>>>> only "pair-wise union",
>>>> according to the axiom of union.
>>>
>>> No.
>>> https://en.wikipedia.org/wiki/Axiom_of_union
>>> ⎛ Informally, the axiom states that
>>> ⎜ for each set x there is a set y
>>> ⎜ whose elements are precisely
>>> ⎝ the elements of the elements of x.
>>
>> "In-formally [naively], ...."
>
> 'Informally' isn't 'naively'.
>
> ⎛ In the formal language of the Zermelo–Fraenkel axioms,
> ⎜ the axiom reads:
> ⎝ ∀A∃B∀c(c∈B⟺∃D(c∈D∧D∈A))
> -- ibid.
>
>

Yeah, "pair-wise".

I'm telling you, I am not wrong,
and for a long time, I am not under-informed,
about ZF and ZFC set theories.

Mistakes to the contrary
are wrong and/or under-informed.