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Date: Wed, 10 Jul 2024 08:09:19 -0500
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Subject: Re: DDD correctly emulated by HHH cannot possibly halt
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From: olcott <NoOne@NoWhere.com>
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On 7/10/2024 6:24 AM, Richard Damon wrote:
> On 7/9/24 11:08 PM, olcott wrote:

_DDD()
[00002163] 55         push ebp      ; housekeeping
[00002164] 8bec       mov ebp,esp   ; housekeeping
[00002166] 6863210000 push 00002163 ; push DDD
[0000216b] e853f4ffff call 000015c3 ; call HHH(DDD)
[00002170] 83c404     add esp,+04
[00002173] 5d         pop ebp
[00002174] c3         ret
Size in bytes:(0018) [00002174]

> 
> You are just proving you don't know what you are talking about.
> 
> The emulation of DDD by HHH can't make it there, but the DDD that was 
> emulated only a finite number of steps by HHH will, after the HHH aborts 
> its emulation and returns to its caller (which was DDD).
Anyone that sufficiently understands the semantics of
the x86 language understands that:

*DDD correctly emulated by any pure function HHH that*
*correctly emulates 1 to ∞ steps of DDD can't make it*
*past its own machine address 0000216b*

No sense us ever talking about this again because you
chose to either remain ignorant or lie and this isn't
going to change.

You probably would not accept the view of any world
class expert thus indicate that between ignorant
and liar you would choose liar.



-- 
Copyright 2024 Olcott

"Talent hits a target no one else can hit;
  Genius hits a target no one else can see."
  Arthur Schopenhauer