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Path: ...!news.mixmin.net!proxad.net!feeder1-2.proxad.net!usenet-fr.net!pasdenom.info!from-devjntp Message-ID: <TI_u6uFeEL3CZNElrYOrAu9rfm0@jntp> JNTP-Route: nemoweb.net JNTP-DataType: Article Subject: Re: E =?UTF-8?Q?=3D=20=33/=34=20mc=C2=B2=20or=20E=20=3D=20mc=C2=B2=3F=20T?= =?UTF-8?Q?he=20forgotten=20Hassenohrl=20=31=39=30=35=20work=2E?= References: <309fb33a3a66f01873fdc890e899a968@www.novabbs.com> Newsgroups: sci.physics.relativity JNTP-HashClient: 6VwahwId8GjORqKyzLjRK1LVvag JNTP-ThreadID: 309fb33a3a66f01873fdc890e899a968@www.novabbs.com JNTP-Uri: https://www.nemoweb.net/?DataID=TI_u6uFeEL3CZNElrYOrAu9rfm0@jntp User-Agent: Nemo/1.0 JNTP-OriginServer: nemoweb.net Date: Sun, 01 Dec 24 12:19:39 +0000 Organization: Nemoweb JNTP-Browser: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/131.0.0.0 Safari/537.36 Injection-Info: nemoweb.net; posting-host="e8cbf2474b472b9bb79db3dccb6a856bc1d05409"; logging-data="2024-12-01T12:19:39Z/9124885"; posting-account="4@nemoweb.net"; mail-complaints-to="julien.arlandis@gmail.com" JNTP-ProtocolVersion: 0.21.1 JNTP-Server: PhpNemoServer/0.94.5 MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit X-JNTP-JsonNewsGateway: 0.96 From: Richard Hachel <r.hachel@liscati.fr.invalid> Bytes: 2311 Lines: 36 Le 01/12/2024 à 01:28, hertz778@gmail.com (rhertz) a écrit : > Now, E = 3/4 mc² or E = mc²? E=mc².sqrt(1+Vr²/c²) If Vr~0 then E=mc². If a mass is at rest in a system, it has no real speed in this system. Nor any observable speed since Vo=Vr/sqrt(1+Vr²/c²) Its only displacement is in time, and only the energy of displacement in time is counted. E=mc² is the energy of a particle by its passage in time. If, in addition, the particle moves in space, it also takes on an energy of movement (not to be confused with kinetic energy). This energy is E=mVr². It is extremely simple. Since this does not add longitudinally since the axis of time and the axis of movement are perpendicular, we must call upon Pythagoras. E=sqrt[(mc²)²+(mVr²)²] E=mc².sqrt(1+Vr²/c²) and, if Vr=Vo/sqrt(1-Vo²/c²) So : E=mc²/sqrt(1-Vo²/c²) It's that simple. R.H.