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Path: ...!feeds.phibee-telecom.net!2.eu.feeder.erje.net!feeder.erje.net!proxad.net!feeder1-2.proxad.net!usenet-fr.net!pasdenom.info!from-devjntp Message-ID: <UqTpLIJxvD4VcXT01kWm7g9OGtU@jntp> JNTP-Route: news2.nemoweb.net JNTP-DataType: Article Subject: Re: Incorrect mathematical integration References: <EKV4LWfwyF4mvRIpW8X1iiirzQk@jntp> <v7h59v$3mabh$1@dont-email.me> Newsgroups: sci.physics.relativity JNTP-HashClient: o3VJi-moovooXmYvli4QccV7YmY JNTP-ThreadID: Ptg0buW51I-Cbbzx-mVW15r6pQg JNTP-Uri: http://news2.nemoweb.net/?DataID=UqTpLIJxvD4VcXT01kWm7g9OGtU@jntp User-Agent: Nemo/0.999a JNTP-OriginServer: news2.nemoweb.net Date: Sat, 20 Jul 24 21:55:07 +0000 Organization: Nemoweb JNTP-Browser: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/126.0.0.0 Safari/537.36 Injection-Info: news2.nemoweb.net; posting-host="e8cbf2474b472b9bb79db3dccb6a856bc1d05409"; logging-data="2024-07-20T21:55:07Z/8956892"; posting-account="4@news2.nemoweb.net"; mail-complaints-to="julien.arlandis@gmail.com" JNTP-ProtocolVersion: 0.21.1 JNTP-Server: PhpNemoServer/0.94.5 MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit X-JNTP-JsonNewsGateway: 0.96 From: Richard Hachel <r.hachel@wanadou.fr> Bytes: 2257 Lines: 31 Le 20/07/2024 à 22:05, "Paul.B.Andersen" a écrit : > I suppose this means that the equation is incorrect according to > your theory. Not just with my theory, but with the reality of things. You can't add carrots and turnips, and that's what physicists believe they can do by adding local infinitesimal durations to find a global time. This is a colossal mistake. > So please show the equation for the proper time as a function of > the velocity and the time in the inertial system, which is > correct physically and mathematically according to your theory. I've already given all that away for a long time. I take the main equations again. To: time in the laboratory (or terrestrial), observable time. Tr: proper time, tau. a: acceleration x=(1/2)a.Tr² x=(c²/a)[sqrt(1+a²To²/c²) -1] To=(x/c)sqrt(1+2c²/ax) Tr=sqrt(2x/a) To=Tr.sqrt(1+(1/4)a².Tr²/c²) R.H.