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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: DDD correctly emulated by HHH is Correctly rejected as
 non-halting V2
Date: Mon, 15 Jul 2024 08:59:36 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Sun, 14 Jul 2024 22:35:03 -0500 schrieb olcott:
> On 7/14/2024 10:02 PM, Mike Terry wrote:
>> On 15/07/2024 01:20, joes wrote:
>>> Am Sun, 14 Jul 2024 09:00:55 -0500 schrieb olcott:
>>>> On 7/14/2024 3:29 AM, joes wrote:
>>>>> Am Sat, 13 Jul 2024 18:33:53 -0500 schrieb olcott:
>>>>>> On 7/13/2024 6:26 PM, joes wrote:

>>>> [0000217a][0015e2dc][0000217f] e853f4ffff call 000015d2 ; call
>>>> HHH(DDD) Local Halt Decider: Infinite Recursion Detected Simulation
>>>> Stopped
>>> How is this detected?
>> PO seems not to want to answer you, as I notice you've asked this
>> question more than once and PO dodges a direct response, so I'll try.
>> (Alternatively, PO has provided a link to his source code in the past,
>> so if you can find that link you can just look the answer yourself -
>> the functions are all in his halt7.c file, which is compiled but not
>> linked, then the obj file is interpreted within his x86utm.exe (source
>> also given in the link.  The link might not reflect his current code??)
Thank you. I didn't bother digging through their code, and they refused
to give the abortion criterion.

>> HHH [outer HHH only!] examines a global trace table of simulated
>> instruction (from all simulation levels merged together).  The
>> particular message "Infinite Recursion Detected Simulation Stopped"
>> seems to be issued when:
>> -  last instruction is a CALL -  working backwards through the merged
>> trace table, another CALL is encountered -  ..which is issued at the
>> same address -  ..and is calling to the same address -  ..and no
>> "conditional branch" instructions occur in the trace table
>>       between the two call instructions
>> 
>> KEY TO NOT BEING MISLED BY THE ABOVE:
>> 
>> 0. The "Infinite Recursion Detected Simulation Stopped" message is just
>> a printf.
>>     It does not prove that /actual/ infinite recursion was detected -
>>     on the contrary,
>>     all here but PO realise that the recursion detected is just
>>     finite recursion.
>> 
>> 1. The trace table being examined is NOT an x86 processor trace - it is
>> a "merged simulation trace" containing entries for ALL SIMULATION
>>     LEVELS.
>>     So the two CALL instructions are not referring to one single x86
>> processor.
> When emulated DDD calls HHH(DDD) the outer HHH emulates itself emulating
> DDD.
> I think that joes does not understand these things.

>>     Typically, the last call instruction is from a deeper nested
>>     simulation than the earlier detected call instruction.  The outer
>>     simulations are all
>>     still running, but do not appear in the trace table or logs
>> presented by PO due to the next note.
>> 
>> 2. The searched trace table is filtered to only contain instructions
>> within the C function D/DD/DDD/.. !!
>>     YES, YOU READ THAT RIGHT!  ALL CODE IN HHH IS TOTALLY IGNORED,
>> INCLUDING
>>     THE CONDITIONAL BRANCH INSTRUCTIONS THAT ARE TESTING THE VERY
>>     ABORT TESTS THAT CAUSE OUTER HHH TO ABORT.
>> 
>> 3. Inner HHH's do not perform the same tests as above, because they
>> inspect a global
>>     variable which tells them they are inner HHH's.  Yeah, that means
>> the simulation
>>     is completely broken logically... [but... the outer HHH will
>>     abort first, so
>>     PO might argue the outcome will be the same, even though
>>     logically it is broken...]
Ah, and here I believed them when they said they had rewritten it.

>>  > Is it also triggered when calling a function in a loop?
>> Not sure what you mean.  Calling a function in a loop ends if the loop
>> ends, right?  What loop are you thinking of?
>> Anyhow, provided the call instructions are physically located in
>> function D() [i.e. not H() or something called from H] I guess it would
>> match.  But the C function D has only one call instruction, which isn't
>> in a loop!
I wondered about just calling the same function repeatedly with the same
parameters (on the same simulation level).

> Any input that must be aborted to prevent the non termination of
> simulating termination analyzer HHH necessarily specifies non-halting
> behavior or it would never need to be aborted.
It's just that the input HHH halts and does not need to be aborted.

-- 
Am Fri, 28 Jun 2024 16:52:17 -0500 schrieb olcott:
Objectively I am a genius.