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From: Richard Hachel <r.hachel@tiscali.fr>
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Le 02/02/2025 à 23:55, "Chris M. Thomasson" a écrit :
> On 1/23/2025 2:51 AM, Peter Fairbrother wrote:
>> On 22/01/2025 13:48, Richard Hachel wrote:
>>> x²+4x+5=0
>>>
>>> This equation has no root, and it never will.
>> 
>> -3.6180339887499
>> -1.3819660112501
> 
> -2-1i
> -2+1i
> 
> The two roots have non-zero imaginary parts, so they are not reals.
> 
> (-2-1i)²+4(-2-1i)+5 = 0
> (-2+1i)²+4(-2+1i)+5 = 0
> 
> :^)

This is obviously very true.
But it poses a small problem for me that I can't quite explain.
I'll think about that.

R.H.