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X-Received: by 2002:a05:620a:8f10:b0:76f:148e:29d9 with SMTP id rh16-20020a05620a8f1000b0076f148e29d9mr80121qkn.8.1693245234453; Mon, 28 Aug 2023 10:53:54 -0700 (PDT) X-Received: by 2002:a17:902:dac2:b0:1af:f80f:185d with SMTP id q2-20020a170902dac200b001aff80f185dmr9622522plx.4.1693245234140; Mon, 28 Aug 2023 10:53:54 -0700 (PDT) Path: ...!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.physique Date: Mon, 28 Aug 2023 10:53:53 -0700 (PDT) In-Reply-To: <66a4b6ce-2107-430e-8ae9-8679850a9412n@googlegroups.com> Injection-Info: google-groups.googlegroups.com; posting-host=2001:861:8bb7:5500:d9e1:c669:cdf9:6b57; posting-account=PKzfqAoAAAC4-vQRW_wt6WFB3xnoeWfi NNTP-Posting-Host: 2001:861:8bb7:5500:d9e1:c669:cdf9:6b57 References: <8x12bqtO5oUQqcTYBlZBIOrQHqg@jntp> <Mw9eS_QWYVCTuDanP3Jl0Qvgm04@jntp> <uatosi$595$1@shakotay.alphanet.ch> <MGib2lAHawOTHU1x6u9Kq0oa0as@jntp> <uavh9v$nlq$1@shakotay.alphanet.ch> <fqoYlxuAKD45Kle-JEVjs_LKNiQ@jntp> <ucd1pk$jtr4$2@dont-email.me> <z1M6_IjykgdtQ5pPWopzVJg-PW8@jntp> <ucd2ld$jtr4$5@dont-email.me> <ucerf6$b45$1@shakotay.alphanet.ch> <fsww8AQxnZECLCbyx7p2TAr3AeE@jntp> <66a4b6ce-2107-430e-8ae9-8679850a9412n@googlegroups.com> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <be907370-2782-471f-8ee9-82b8ca744523n@googlegroups.com> Subject: Re: Petite question simple. From: Richard Verret <rverret97@gmail.com> Injection-Date: Mon, 28 Aug 2023 17:53:54 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Bytes: 2756 Lines: 20 Le 28/08/2023 =C3=A0 14:48, Julien Arlandis a =C3=A9crit : > Le 28/08/2023 =C3=A0 14:08, Richard Hachel a =C3=A9crit : >> A noter que si l'on veut donner les additions de vitesses observables lo= ngitudinales, =C3=A0 partie de l'=C3=A9quation g=C3=A9n=C3=A9rale des VO, e= n posant cos=C2=B5=3D1 et sin=C2=B5=3D0, on a : >> w=3Dv+u/(1+vu/c=C2=B2) >> Et pour les transversales (cos=C2=B5=3D0 et sin=C2=B5=3D1) : w=3Dsqrt(v= =C2=B2+u=C2=B2-v=C2=B2u=C2=B2/c=C2=B2) >> Comme chacun le sait. >> On peut faire la m=C3=AAme chose ici pour les vitesses r=C3=A9elles. >>=20 >> On pose pour les longitudinales (cos=C2=B5=3D1, sin=C2=B5=3D0) et on a: >> Wr=3DVr.sqrt(1+Ur=C2=B2/c=C2=B2) + Ur.sqrt(1+Vr=C2=B2/c=C2=B2) >> et pour les transversales (cos=C2=B5=3D0, sin=C2=B5=3D1) >> Wr=3Dsqrt[Vr=C2=B2+Ur=C2=B2+Vr=C2=B2Ur=C2=B2/c=C2=B2] > C'est quoi Ur, Vr ? Ur et Vr sont les vitesses r=C3=A9elles, celles du monde r=C3=A9el qui est = diff=C3=A9rent du monde perceptible (observable). > En relativit=C3=A9 il n'y a qu'une seule vitesse not=C3=A9e u et v. u et v =C3=A7a fait deux vitesses, pas une.