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From: wij <wyniijj5@gmail.com>
Newsgroups: comp.theory
Subject: Re: Any honest person that knows the x86 language can see...
 predict correctly
Date: Thu, 01 Aug 2024 12:03:36 +0800
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On Wed, 2024-07-31 at 22:51 -0500, olcott wrote:
> On 7/31/2024 10:08 PM, wij wrote:
> > On Tue, 2024-07-30 at 18:50 -0500, olcott wrote:
> > >=20
> > > It is not supposed to be a general solution to the halting problem.
> > > it only shows how the "impossible" input is correctly determined
> > > to be non halting.
> > >=20
> >=20
> > But how do you determine it is non-halting?
> >=20
> > As I know you are even unable to define what 'halt' mean !!!
> >=20
> I have done this thousands of times and after someone
> has read these thousands of times they say that I never
> said it once.
>=20
> void DDD()
> {
> =C2=A0=C2=A0 HHH(DDD);
> =C2=A0=C2=A0 return;
> }
>=20
> int main()
> {
> =C2=A0=C2=A0 HHH(DDD);
> }
>=20
> If DDD correctly emulated by HHH cannot possibly
> reach its return instruction then it never halts.
>=20
>=20

That's right, HHH(DDD) as shown should never halt.

But The Halting Problem asks HHH to return 1 or 0 (so to speak, because you
don't know the detail).

Since HHH does not return 1 or 0 to answer the question, it is not a decide=
r.
You are dealing with POO Problem.