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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory
Subject: Re: DDD specifies recursive emulation to HHH and halting to HHH1
Date: Thu, 27 Mar 2025 19:51:46 -0400
Organization: i2pn2 (i2pn.org)
Message-ID: <d016e11a2de50634e4b6dd14b9fe192066a00d0b@i2pn2.org>
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On 3/27/25 7:40 PM, olcott wrote:
> On 3/27/2025 4:56 PM, joes wrote:
>> Am Thu, 27 Mar 2025 13:10:46 -0500 schrieb olcott:
>>> On 3/27/2025 6:02 AM, Richard Damon wrote:
>>>> On 3/26/25 11:47 PM, olcott wrote:
>>>>> On 3/26/2025 10:28 PM, Richard Damon wrote:
>>>>>> On 3/26/25 11:09 PM, olcott wrote:
>>>>>>> On 3/26/2025 8:22 PM, Richard Damon wrote:
>>
>>>>>>>> Non-Halting is that the machine won't reach its final staste even
>>>>>>>> if an unbounded number of steps are emulated. Since HHH doesn't do
>>>>>>>> that, it isn't showing non-halting.
>>>>>>> DDD emulated by any HHH will never reach its final state in an
>>>>>>> unbounded number of steps.
>>>>>> But DDD emulated by an actually correct emulator will,
>>>>> If you were not intentionally persisting in a lie you would
>>>>> acknowledge the dead obvious that DDD emulated by HHH according to the
>>>>> semantics of the x86 language cannot possibly correctly reach its
>>>>> final halt state.
> 
>> Yes, HHH is not a correct simulator.
>>
> 
> In other words you either disagree with the x86 language
> or don't have a clue about it.
> 

No, it is YOU who does, as you think the x86 language somewhere has a 
definition that the call to some address starts an x86 level emulator.

It has no such thing, a call instruction only transfers execution to the 
subroutine called.

Even at a meta-logic level of emulation, a call to an emulator only 
become equivalent to calling the program emulated if the emulator is 
actually a COMPLETE and correct emulator, no aborting allowed.

Sorry, you are just proving that all your logic is based on FRAUD and lies.