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From: tomyee3@gmail.com (ProkaryoticCaspaseHomolog)
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Subject: Re: Want to prove =?UTF-8?B?RT1tY8KyPyBVbml2ZXJzaXR5IGxhYnMgc2hvdWxkIHRy?=
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Date: Wed, 20 Nov 2024 04:01:43 +0000
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On Wed, 20 Nov 2024 1:02:37 +0000, rhertz wrote:

> On Wed, 20 Nov 2024 0:48:23 +0000, gharnagel wrote:

>> Might as well stick with Al and use a thicker wall.  That
>> puts all the pressure on the scales though, but I think that's
>> a much easier problem than weighing actual 455 nm light.  Just
>> keep pumping 5W into the cavity for 72 hours, and the hole
>> for introducing the 5W could be a sapphire disc with a 455 nm
>> transmission band, otherwise, too much energy would be lost.
>>
>> What do you think, still out of bounds?  Yeah, I think so.
>
> Use this site instead:
>
> https://aluminyumburada.com/en/aluminium-weight-calculation
>
> Weight of a sheet of 100x100mmx0.1mm (Alloy 5083) is 3.0 grams.
>
> Not bad for my estimation (2 gr) for the weight of the cavity, with
> inner surface of 7,850 mm², and thickness of 0.1 mm.
>
> And it will not melt. Not even heat enough for you to feel it.
>
> Most of the energy will be confined in the inner volume, not in the
> walls, even with 99% reflectivity.

Your estimates look pretty reasonable to me.