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X-Received: by 2002:ac8:5e53:0:b0:3f5:4699:107c with SMTP id i19-20020ac85e53000000b003f54699107cmr2533720qtx.12.1684663147755; Sun, 21 May 2023 02:59:07 -0700 (PDT) X-Received: by 2002:a25:9284:0:b0:b8f:5474:2f33 with SMTP id y4-20020a259284000000b00b8f54742f33mr4137585ybl.5.1684663147527; Sun, 21 May 2023 02:59:07 -0700 (PDT) Path: ...!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: fr.sci.physique Date: Sun, 21 May 2023 02:59:07 -0700 (PDT) In-Reply-To: <4e7aea67-ac93-4ba8-9413-a53b926c61f4n@googlegroups.com> Injection-Info: google-groups.googlegroups.com; posting-host=2001:861:8bb7:5500:e941:f637:9528:9de2; posting-account=PKzfqAoAAAC4-vQRW_wt6WFB3xnoeWfi NNTP-Posting-Host: 2001:861:8bb7:5500:e941:f637:9528:9de2 References: <u0r2k6$161g2$1@dont-email.me> <u13egk$2kc1l$1@dont-email.me> <u13jou$2ko1o$1@dont-email.me> <u13lqv$2l0ir$1@dont-email.me> <u13q9c$2l3vn$1@dont-email.me> <u13que$2kt04$1@dont-email.me> <u13t5s$rq$2@shakotay.alphanet.ch> <u13u8n$2l71c$2@dont-email.me> <eu6-atxrEppmGwQfAd86ghgZ6-U@jntp> <u1434c$2m51m$2@dont-email.me> <T66X88xOsCfsVOT48hqiAurwkDY@jntp> <fe9be762-f1d1-4c40-b169-a6c969839efcn@googlegroups.com> <a9cdb9ee-9582-465e-8355-2d01a8e6b40fn@googlegroups.com> <u4afvv$12ngn$1@dont-email.me> <9dad9664-92d8-4d3d-b230-f2a0fe5d11d0n@googlegroups.com> <u4c7pr$84i$1@shakotay.alphanet.ch> <4e7aea67-ac93-4ba8-9413-a53b926c61f4n@googlegroups.com> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <d25eb635-522d-4781-a5cd-3960067bf38fn@googlegroups.com> Subject: =?UTF-8?Q?Re=3A_Quand_l=27I=2EA=2E_p=C3=A8te_les_plombs_sur_la_RR=2E?= From: Richard Verret <rverret97@gmail.com> Injection-Date: Sun, 21 May 2023 09:59:07 +0000 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Bytes: 2416 Lines: 9 Il y a eu un bug =C3=A0 la fin de mon texte. Je rectifie. L=E2=80=99=C3=A9nergie E d=E2=80=99un point mat=C3=A9riel est telle que dE/= dt =3D Ft v=20 soit dE/dt =3D k m gt v =3D m v gt/sqrt(1 + (v/c)^2) d=E2=80=99o=C3=B9=20 E =3D m c^2 sqrt(1 + (v/c)^2) =3D =CE=B3 mc^2 et une =C3=A9nergie cin=C3=A9= tique Ec =3D (=CE=B3 - 1) m c^2=20 avec =CE=B3 =3D sqrt(1 + (v/c)^2). Lorsque v << c, on obtient les lois de la m=C3=A9canique classique=20 p =3D m v, Ft =3D m gt, Fn =3D m v^2/r et Ec =3D m v^2/2.