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Subject: =?UTF-8?Q?Re=3A_Quand_l=27I=2EA=2E_p=C3=A8te_les_plombs_sur_la_RR=2E?=
From: Richard Verret <rverret97@gmail.com>
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Il y a eu un bug =C3=A0 la fin de mon texte. Je rectifie.

L=E2=80=99=C3=A9nergie E d=E2=80=99un point mat=C3=A9riel est telle que dE/=
dt =3D Ft v=20
soit dE/dt =3D k m gt v =3D m v gt/sqrt(1 + (v/c)^2) d=E2=80=99o=C3=B9=20
E =3D m c^2 sqrt(1 + (v/c)^2) =3D =CE=B3 mc^2 et une =C3=A9nergie cin=C3=A9=
tique Ec =3D (=CE=B3 - 1) m c^2=20
avec =CE=B3 =3D sqrt(1 + (v/c)^2).
Lorsque v << c, on obtient les lois de la m=C3=A9canique classique=20
p =3D m v, Ft =3D m gt, Fn =3D m v^2/r et Ec =3D m v^2/2.