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Path: ...!weretis.net!feeder9.news.weretis.net!i2pn.org!i2pn2.org!.POSTED!not-for-mail From: hertz778@gmail.com (rhertz) Newsgroups: sci.physics.relativity Subject: Re: Gravitational red-shifting in the biggest star. What are the real =?UTF-8?B?Y29sb3JzPw==?= Date: Sat, 28 Sep 2024 02:34:50 +0000 Organization: novaBBS Message-ID: <d53d725fd59b543ff824b3be8893ec92@www.novabbs.com> References: <e92ea2a0a7546bace6a2ccea27d44d00@www.novabbs.com> MIME-Version: 1.0 Content-Type: text/plain; charset=utf-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Info: i2pn2.org; logging-data="3800960"; mail-complaints-to="usenet@i2pn2.org"; posting-account="hWiuCAeR3KEZYJfTvV11n0qrRi6oqW/zjvEZQQGun9A"; User-Agent: Rocksolid Light X-Rslight-Site: $2y$10$.LPnspMp/ofHOD9r966PzuGrnIEzIQCvW3moMB89Tdqc6drKYVU7G X-Rslight-Posting-User: f685b96694175b2ad43ead343ead0a9c0082fe88 X-Spam-Checker-Version: SpamAssassin 4.0.0 Bytes: 2033 Lines: 43 This link illustrates a bit: https://en.wikipedia.org/wiki/Gravitational_redshift Using the most common formula from that link: "To first approximation, gravitational redshift is proportional to the difference in gravitational potential divided by the speed of light squared" Δf/f = Δλ/λ = z = GM/c² (1/R - 1/r) = Φ(R)/c² - Φ(r)/c² G = 6.6743E−11 m^3 kg^−1 s^−2 M = 5E+09 x 1.989E+30 Kg = 9.945E+39 Kg R = 1,700 x 634,000 Km = 1,077,800,000,000 m Φ(R)/c² = 6,842,736.59 In comparison, Φ(RSun)/c² = 0.000002327 At r = 10,000,000 R = 10,077,800,000,000,000,000 m Φ(r)/c² = 0.684273659 Δf/f = Δλ/λ = z = 6,842,736 The z-value can be expressed succinctly in terms of the escape velocity at R, since the gravitational potential is equal to half the square of the escape velocity, thus: z = 1/2 (v_escape/c)² v_escape = 3699.4 c But then, light can escape from UY Scuti. Yet, it was discovered in 1860. WHAT IS WRONG WITH MY CALCULATIONS, BASED ON THE WIKI LINK?