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From: joes <noreply@example.org>
Newsgroups: sci.math
Subject: Re: 2N=E
Date: Sun, 3 Nov 2024 15:55:56 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
Message-ID: <d76e020d7e690a7a993014bc977b979186b70da6@i2pn2.org>
References: <vb4rde$22fb4$2@solani.org> <vfgqa8$39o4h$1@dont-email.me>
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Am Sun, 03 Nov 2024 12:56:48 +0100 schrieb WM:
> On 03.11.2024 09:50, joes wrote:
>> pparently you do think that there is a natural n such that 2^n is
>> infinite.
> If all naturals are there, then no further one is available. But
> doubling all yields a greater number than all.
> In actual infinity there is no way to avoid this.
We don't need any further ones because we ALREADY HAVE ALL OF THEM,
even including the doubles.

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.