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From: joes <noreply@example.org>
Newsgroups: sci.math
Subject: Re: The non-existence of "dark numbers"
Date: Mon, 24 Mar 2025 00:58:29 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
Message-ID: <d9db7b4c0bb13dcf9babbcb95eb004365b02d196@i2pn2.org>
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Am Sun, 23 Mar 2025 18:23:49 +0100 schrieb WM:
> On 22.03.2025 20:33, Jim Burns wrote:
>> On 3/22/2025 5:19 AM, WM wrote:
> 
>>> It is infinite but nevertheless obeys the logic of lossless exchanges
>>> do not suffer losses.
>> Infinite sets don't need to obey the logic of lossless exchanges do not
>> suffer losses.
> Every set does because the claim concerns always only one finite term:
> One single exchange.
Exactly. It does not concern the result, the limit.

> The loss, if happened, had to happe at a finite index.
Uh no, then we wouldn't have an infinite sequence. It is your perennial
failure to conceptualise the infinite as something after every and all
finite indices.

>>> The reason is that all pairs of the bijection proving same cardinality
>>> have infinitely many dark successors which cannot be bijected.
>> A bijection which does not biject everything is not a bijection,
> So it is! But it is impossible to prove everything in Cantor's
> bijections. Almost all elements follow upon every defined pair.
....which are bijected just the same. Why should that change?

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.