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From: hertz778@gmail.com (rhertz)
Newsgroups: sci.physics.relativity
Subject: Re: Want to prove =?UTF-8?B?RT1tY8KyPyBVbml2ZXJzaXR5IGxhYnMgc2hvdWxkIHRy?=
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Date: Wed, 20 Nov 2024 00:47:21 +0000
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To make things more realistic and feasible, I changed the material of
the cavity for aluminum, which has a reflectivity of 99%. I figure out
the weight of each cavity as being 2 grams.

The aluminum coating on the inside has, on purpose, an irregular surface
in the order of nanometers, so the laser beam will disperse in each
bounce.

I suggest that the laser output be dispersed by a vibrating lens, prior
to its entry to the cavity. In this way, the beam will be continuously
dispersed. Even more, 4 or 5 different lasers (total power = 5 W) be
placed in such a way that they cover the entire volume of the cavity,
accelerating the process of energy spread in its volume.

New calculations, using aluminum:



h = 6.62607E-34	J.sec
λ = 5.50E-07 m
c = 3.00E+08 m/s
E(photon) = 1.21E-48 Joules

5 W = 5 Joules/sec = 4.12E+48 photons/sec
5 Joules/hour = 1.48E+52 photons/hour

Inner surface of cavity = 7.85E+03 mm²
Area of laser spot  = 	 3.14159 mm²
	                 2,500	spots

Time between hits = 	3.333E-10 seconds (10 cm avg. trajectory)
	                3.00E+09 bounces/sec

photon hits/sec in the cavity = 1.37E+39
photons hit/sec x spot = 	5.4879643E+35

Reflectivity with aluminum = 	99.0%
photons reflected/sec x spot = 	5.4330846E+35
photons absorbed/sec x spot = 	5.49E+33

energy lost/sec x spot = 	6.67E-15 J
energy lost/sec in the cavity = 1.67E-11 J
energy lost/Hr in the cavity = 	6.00E-08 J
energy lost/Hr in the cavity = 	1.43E-08 cal/Hr


energy lost in 72 Hr, in the cavity = 	1.032E-06 calories

Even if I made errors in the order of 1,000:1, still the heat absorbed
is insignificant (0.00103 calories).




AS A REFERENCE:

1 calorie is the heat that raises 1"C to one gram of water.

With this new arrangement and materials, proving/disproving E=mc² should
be much easier and cheap. The weight increment is in the order of 9 μN
(1.0368 μgrams of MASS) can be measured with EM balances of $ 10,000.