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From: joes <noreply@example.org>
Newsgroups: comp.theory
Subject: Re: Who here is too stupid to know that DDD simulated by HHH cannot
 reach its own return?
Date: Wed, 7 Aug 2024 18:25:31 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Wed, 07 Aug 2024 08:40:31 -0500 schrieb olcott:
> On 8/7/2024 2:22 AM, Mikko wrote:
>> On 2024-08-05 15:00:12 +0000, olcott said:
>>> On 8/5/2024 2:44 AM, Mikko wrote:
>>>> On 2024-08-04 13:11:56 +0000, olcott said:
>>>>> On 8/4/2024 1:26 AM, Fred. Zwarts wrote:
>>>>>> Op 03.aug.2024 om 17:20 schreef olcott:>>

>>>> In another message you have said that when HHH simulates itself
>>>> simulating DDD is does not simulate itself simulating itself
>>>> simulating DDD. You have not told whether it makes a cup of coffee.
>>>> Neither action can be seen in the traces you have shown.
>>>>
>>> HHH and HH and the original H have proved that they simulate
>>> themselves simulating DDD, DD and P for three years now.
>> 
>> Your trace don't show siulation of exectuion differently from
>> simulation of simulation of execution.
>> 
> It does but it is too difficult to dig it out of emulations of emulators
> emulating inputs.
You could make it clearer by prefixing the simulation level.

> As soon as the first HHH sees the second DDD about to invoke a third HHH
> it aborts the emulation. At this point DDD, the second HHH and the
> second DDD all immediately stop running and HHH returns 0 to main.
And HHH concludes that the second invocation of itself would somehow
not also abort but run forever, and then returns that itself wouldn't
halt, and halts. ???

-- 
Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:
It is not guaranteed that n+1 exists for every n.