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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory
Subject: Re: Who knows that DDD correctly simulated by HHH cannot possibly
 reach its own return instruction final state?
Date: Mon, 5 Aug 2024 22:52:53 -0400
Organization: i2pn2 (i2pn.org)
Message-ID: <f8c03422f0984d738d1a6b64e27018d3cba11aa9@i2pn2.org>
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On 8/5/24 10:25 PM, olcott wrote:
> On 8/5/2024 8:32 PM, Richard Damon wrote:
>> On 8/5/24 8:07 PM, olcott wrote:
>>> On 8/5/2024 5:59 PM, Richard Damon wrote:
>>>> On 8/5/24 9:49 AM, olcott wrote:
>>>>> On 8/5/2024 2:39 AM, Mikko wrote:
>>>>>> On 2024-08-04 18:59:03 +0000, olcott said:
>>>>>>
>>>>>>> On 8/4/2024 1:51 PM, Richard Damon wrote:
>>>>>>>> On 8/4/24 9:53 AM, olcott wrote:
>>>>>>>>> On 8/4/2024 1:22 AM, Fred. Zwarts wrote:
>>>>>>>>>> Op 03.aug.2024 om 18:35 schreef olcott:
>>>>>>>>>  >>>> ∞ instructions of DDD correctly emulated by HHH[∞] never
>>>>>>>>>>> reach their own "return" instruction final state.
>>>>>>>>>>>
>>>>>>>>>>> So you are saying that the infinite one does?
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> Dreaming again of HHH that does not abort? Dreams are no 
>>>>>>>>>> substitute for facts.
>>>>>>>>>> The HHH that aborts and halts, halts. A tautology.
>>>>>>>>>
>>>>>>>>> void DDD()
>>>>>>>>> {
>>>>>>>>>    HHH(DDD);
>>>>>>>>>    return;
>>>>>>>>> }
>>>>>>>>>
>>>>>>>>> That is the right answer to the wrong question.
>>>>>>>>> I am asking whether or not DDD emulated by HHH
>>>>>>>>> reaches its "return" instruction.
>>>>>>>>
>>>>>>>> But the "DDD emulated by HHH" is the program DDD above,
>>>>>>>
>>>>>>> When I say DDD emulated by HHH I mean at any level of
>>>>>>> emulation and not and direct execution.
>>>>>>
>>>>>> If you mean anything other than what the words mean you wihout
>>>>>> a definition in the beginning of the same message then it is
>>>>>> not reasonable to expect anyone to understand what you mean.
>>>>>> Instead people may think that you mean what you say or that
>>>>>> you don't know what you are saying.
>>>>>>
>>>>>
>>>>> If you don't understand what the word "emulate" means look it up.
>>>>>
>>>>> DDD (above) cannot possibly reach its own "return" instruction halt
>>>>> state when its machine code is correctly emulated by HHH.
>>>>>
>>>>
>>>> Only because an HHH that does so never returns to anybody.
>>>>
>>>
>>> Do you really not understand that recursive emulation <is>
>>> isomorphic to infinite recursion?
>>>
>>
>> Not when the emulation is conditional.
>>
> 
> Infinite_Recursion() meets the exact same condition that DDD
> emulated by HHH makes and you know this. Since you are so
> persistently trying to get away contradicting the semantics
> of the x86 language the time is coming where there is zero
> doubt that this is an honest mistake.
> 

Not for any of the DDD built on an HHH that answers, as those do 
CONDITIONAL emulation, and thus we DO HAVE a conditional in the loop.

> Ben does correctly understand that the first half of the Sipser
> approved criteria is met. Even Mike finally admitted this.
> 
> Those that disagree either are totally lacking in even basic
> knowledge of C or are liars.

That is the description of you, a liar who is totally lacking in even 
basic knowledge of C, as you don't understand that the PROGRAM DDD 
includes the HHH that it calls.

> 
>>> void Infinite_Recursion()
>>> {
>>>    Infinite_Recursion();
>>>    return;
>>> }
>>>
>>> Does infinite recursion ever reach its own "return"
>>> instruction halt state?
>>>
>