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Path: ...!weretis.net!feeder9.news.weretis.net!i2pn.org!i2pn2.org!.POSTED!not-for-mail From: Richard Damon <richard@damon-family.org> Newsgroups: sci.math Subject: Re: How many different unit fractions are lessorequal than all unit fractions? Date: Fri, 13 Sep 2024 16:52:34 -0400 Organization: i2pn2 (i2pn.org) Message-ID: <fe6f891d4eab6478c32f1d619c32ab6d904cf539@i2pn2.org> References: <vb4rde$22fb4$2@solani.org> <vbnuqq$2it4a$2@dont-email.me> <vbp9dk$2u3sh$1@dont-email.me> <vbq4ve$31fu6$10@dont-email.me> <fd09e9afa6b0c3041b90c5d788681bb2c92f9d2e@i2pn2.org> <vbs9v8$3l368$3@dont-email.me> <405557f7289631d63264c712d137244c940b9926@i2pn2.org> <vbsroa$3mvi7$2@dont-email.me> <vbt0fs$3pr1d$1@dont-email.me> <vbt15n$3qapk$1@dont-email.me> <btbO__HYVIMPfoOcmXp4_whV8-8@jntp> <vbums6$8kdn$1@dont-email.me> <vbv9i7$bpjh$2@dont-email.me> <13c08e96ad635f8142b38d89863a80caf17a32a8@i2pn2.org> <vc1mfe$u3ec$2@dont-email.me> <4faa63d0ff8c163f01a38736aeb5732184218a29@i2pn2.org> <vc1uu8$u3ec$9@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Fri, 13 Sep 2024 20:52:34 -0000 (UTC) Injection-Info: i2pn2.org; logging-data="1949495"; mail-complaints-to="usenet@i2pn2.org"; posting-account="diqKR1lalukngNWEqoq9/uFtbkm5U+w3w6FQ0yesrXg"; User-Agent: Mozilla Thunderbird Content-Language: en-US X-Spam-Checker-Version: SpamAssassin 4.0.0 In-Reply-To: <vc1uu8$u3ec$9@dont-email.me> Bytes: 3149 Lines: 45 On 9/13/24 2:05 PM, WM wrote: > On 13.09.2024 17:52, Richard Damon wrote: >> On 9/13/24 11:41 AM, WM wrote: > >>> Between [0, 1] and (0, 1] there is nothing, there is not a spot or >>> point of the interval. >>> >> But that doesn't mean there is a lowest most point in (0, 1] as any >> point you might want to call it will have another point between it >> and 0. > > I will not call any point but consider all points. There is no point > smaller than all points in the open interval but a smallest one. Only 0 > is smaller than all. Nope, you just don't understand how infinte sets work, because you mind just can't handle it. What ever value the "smallest" point has, call it x, there MUST be a smaller point at x/2, so there is not smallest. Not till you can find a positive value such that x < x/2. Sorry. >> >> Note, I said between the point your THINK is the first, there is no >> such point, and thus you are agreeing to that fact. >> >> You can only have a first point in the open interval if the interval >> has only a finite number of points, > > No, that is your big mistake. In the interval [0, 1] there is a point > next to 0 and a point next to 1, and infinitely many are beteen them. > > Regards, WM > How? What value could it have? If it is x, what about the fact that x/2 will be between it an 0. You are just proving that you logic have exploded your brains to smithereens due to its inconsistency. You are just proving your logic can't handle what you are talking about because it just is totally inconsistant.