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From: Richard Damon <richard@damon-family.org>
Newsgroups: sci.math
Subject: Re: Incompleteness of Cantor's enumeration of the rational numbers
(extra-ordinary)
Date: Wed, 8 Jan 2025 20:26:52 -0500
Organization: i2pn2 (i2pn.org)
Message-ID: <ff1fe002014bf5951a98e2061cb63ad93976a808@i2pn2.org>
References: <vg7cp8$9jka$1@dont-email.me> <vkp0fv$b7ki$2@dont-email.me>
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In-Reply-To: <vlmst2$2vjr0$3@dont-email.me>
On 1/8/25 5:06 PM, WM wrote:
> On 08.01.2025 20:19, Jim Burns wrote:
>> On 1/8/2025 4:16 AM, WM wrote:
>>> On 08.01.2025 00:50, Jim Burns wrote:
>>
>>>> The cardinal:ordinal distinction
>>>> -- which does not matter in the finite domain
>>>> matters in the infinite domain.
>>>
>>> The reason is that
>>> the infinite cardinal ℵ₀ is based on
>>> the mapping of the potentially infinite collection of
>>> natural numbers n,
>>> all of which have
>>> infinitely many successors.
>>> The cardinal ℵ₀ is not based on
>>> the mapping of
>>> the actually infinite set ℕ where
>>> ℕ \ {1, 2, 3, ...} = { }.
>>
>> For each set smaller.than a fuller.by.one set,
>> the cardinal:ordinal distinction doesn't matter.
>> Cardinals and ordinals always go together.
>>
>> For each set smaller.than a fuller.by.one set
>> there is an ordinal of its size in
>> the set ℕ of all finite ordinals.
>>
>> Each set for which
>> there is NOT an ordinal of its size in
>> the set ℕ of all finite ordinals
>> is NOT a set smaller.than a fuller.by.one set.
>
> The set {1, 2, 3, ...} is smaller by one element than the set {0, 1, 2,
> 3, ...}. Proof: {0, 1, 2, 3, ...} \ {1, 2, 3, ...} = {0}. Cardinality
> cannot describe this difference because it covers only mappings of
> elements which have almost all elements as successors.
>
> Regards, WM
>
But Alelph_0, the size of the second, is also the size of the first, as
Aleph_0 - 1 is Aleph_0.
The fact that your brain can't handle that fact of infinite numbers is
YOUR problem, not a problem with mathematics.