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From: immibis <news@immibis.com>
Newsgroups: comp.theory
Subject: Re: Proving my 2004 claim that some decider/input pairs are incorrect
 questions (NFFC)
Date: Wed, 13 Mar 2024 05:00:05 +0100
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On 13/03/24 04:25, olcott wrote:
>> H COULD halt in a state other than qy or qn and thus make itself wrong.
>>
> No it is not wrong. It is the same as a divide by zero exception.

Is "divide by zero exception" the correct answer to "does this machine 
halt?"?

>> This might be a reasonable extension for a decider, Accept, Reject, 
>> and an "I can't tell". The key is to somehow limit where "I can't 
>> tell" can be used, or it makes the decider useless.
>>
> If it can be limited then it can be limited for H(D,D)
> otherwise when some machine can do it then it can be done.

I don't think you understood what Richard said.

>> Could be a LOT better (but still not meet the original requrements) 
>> then lying by going to Accept or Reject incorrectly.
>>
>> This was actually discussed as an option a while back
> 
> This time you understand how H(D,D) and H1(D,D) work instead
> of simply denying that they do what they did do.

Halting semi-deciders that sometimes output "I can't tell" can still be 
very useful practical tools, however, they do not disprove the halting 
theorem.