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Path: ...!npeer.as286.net!npeer-ng0.as286.net!fu-berlin.de!uni-berlin.de!individual.net!not-for-mail From: Thomas Heger <ttt_heg@web.de> Newsgroups: sci.physics.relativity Subject: Re: A short proof of the inconsistency of the physics of your idiot guru Date: Thu, 3 Oct 2024 09:00:04 +0200 Lines: 61 Message-ID: <lm6tneFg6sqU2@mid.individual.net> References: <17fa988fc89c527f$104027$844270$c2365abb@news.newsdemon.com> Mime-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit X-Trace: individual.net 9HELgiKZz6qxxQAZzN1zjgCeyUwuADxtgxSIa0ledFW7kuRmw8 Cancel-Lock: sha1:QCyBoqj7lXOM3grA09ABvnQQcic= sha256:rKeja/VmhdbQe6WRAtTGt0aZNkDSJVsE5xjAA5hKtcs= User-Agent: Mozilla Thunderbird Content-Language: de-DE In-Reply-To: <17fa988fc89c527f$104027$844270$c2365abb@news.newsdemon.com> Bytes: 2880 Am Mittwoch000002, 02.10.2024 um 11:25 schrieb Maciej Wozniak: > > https://en.wikipedia.org/wiki/Second > As seen, the definition of second loved so > much to be invoked by relativistic morons - > wasn't valid in the time when their idiot guru > lived and mumbled. Up to 1960 it was ordinary > 1/86400 of a solar day, also in physics. > > > Now: an observer moving with c/2 wrt > solar system is measuring the length > of solar day. What is the result predicted > by the Einsteinian physics? > One prediction is - 99766. From the > postulates. The second prediction is - > 86400. From definition. > And similiarly with the prediction of > a measurement of a meridian. If you measure the length of the solar day on Earth from a spaceship receeding away with c/2, then you measure signals from- say- sunrise in Greenwich at the 0° meridian for a day. These signals are measured with onboard clocks. Since light is assumed to travel with c, the signal originated at t_0=6:00 GMT is received at a time, which is t_x1 later. This depends on the distance x_1, by which the spaceship has receded from Earth at t_1 GMT. x= c* t hence t_x1 = x_1/ c A day later on Earth the time at the zero meridian is 6:00 GMT + 1 day. Then another message is sent to the spaceship, which had moved away with c/2 within that day. For this signal the same is valid, but with a different distance x_2, since that spaceship is now further away. The distance from Earth is now x_2 = x_1 + c/2*86400 s. The time needed to reach the ship is therefore t_x2 = (x_1 + c/2*86400 s)/c or: t_x2 = ( x_1/c + (c/c) * (86400/2)s). =t_x1 + 43200 s The length of a day on Earth, if measured from that spaceship is therefore 86400s + 43200 s = 129600 s (in terms of Earth time measures). Whether the crew upon that spaceship encounters a difference in the onboard measurements is a possibility, but should be subject to experiments. TH