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From: Sylvia Else <sylvia@email.invalid>
Newsgroups: sci.physics.relativity
Subject: Re: Newton: Photon falling from h meters increase its energy.
Date: Wed, 15 Jan 2025 11:02:16 +0800
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On 12-Jan-25 1:16 am, rhertz wrote:
> Under Newton, a photon has gravitational mass m, for which it's affected
> by gravity.
> 
> 1) A photon with energy E, falling under gravity effects from height h,
> increases its energy by an amount
> 
> ΔE = +mgh
> 
> Using the equivalence m = E/c^2, its energy when it reaches ground is E
> + ΔE:
> 
> 
> E + ΔE = E (1 + gh/c^2)
> 
> Using Planck's equivalence E = hf, it gives
> 
> f + Δf = f (1 + gh/c^2)
> 
> Then, under Newton, the frequency change is
> 
> Δf/f = +gh/c^2
> 
> The frequency of the photon increase by falling, and is blue-shifted.
> 
> On the other way around, if a photon is escaping from ground, at an
> height h its frequency has decreased by
> 
> Δf/f = -gh/c^2 (red-shifted)
> 
> ******************************************************
> 
> No relativity here. Only requires to accept the existence of
> gravitational mass and a given equivalence mass-energy.

The problem is that this doesn't work. Two observers at different 
heights would see differing numbers of waves passing their respective 
locations per unit time. The observers would conclude that waves were 
accumulating between their two locations, or somehow just vanishing.

Sylvia.