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Path: ...!weretis.net!feeder9.news.weretis.net!feeder8.news.weretis.net!fu-berlin.de!uni-berlin.de!not-for-mail From: "Kevin M. Wilson" <kevinmwilson1956@yahoo.com> Newsgroups: comp.lang.python Subject: Fw: Flubbed it in the second interation through the string: range error... HOW? 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KMW *************************************************** "When you pass through the waters, I will be with you: and when you=C2=A0pa= ss through the rivers, they will not sweep over=C2=A0you. When=C2=A0you wal= k=C2=A0through the fire, you will not be burned: the flames will not set yo= u ablaze."=C2=A0 =C2=A0 =C2=A0=20 Isaiah 43:2 =20 ----- Forwarded Message ----- From: Kevin M. Wilson via Python-list <pyt= hon-list@python.org>To: python-list@python.org <python-list@python.org>Sent= : Tuesday, May 28, 2024 at 10:35:23 PM MDTSubject: Flubbed it in the second= interation through the string: range error... HOW? The following is my effort to understand how to process a string, letter, = by letter: def myfunc(name):=C2=A0 =C2=A0=C2=A0=C2=A0 =C2=A0 index =3D 0=C2=A0 =C2=A0 = howmax =3D len(name)=C2=A0 =C2=A0 # while (index <=3D howmax):=C2=A0 =C2=A0= while (index < howmax):=C2=A0 =C2=A0 =C2=A0 =C2=A0 if (index % 2 =3D=3D 0)= :=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 print('letter to upper =3D {}, i= ndex {}!'.format(name[index], index))=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2= =A0 name =3D name[index].upper()=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 p= rint('if block {} and index {}'.format(name[index], index))=C2=A0 =C2=A0 = =C2=A0 =C2=A0 elif (index % 2 > 0):=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2= =A0 print(index)=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 print('Start: els= eif block, index is {}, letter is {}'.format(index, name))=C2=A0 =C2=A0 =C2= =A0 =C2=A0 =C2=A0 =C2=A0 # print('letter to lower =3D {}'.format(name[index= ]))=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 # print('Already lowercase do = noting: name =3D {}'.format(name[index]))=C2=A0 =C2=A0 =C2=A0 =C2=A0 index = +=3D 1=C2=A0 =C2=A0 =C2=A0 =C2=A0 # index =3D name.upper()=C2=A0 =C2=A0 =C2= =A0 =C2=A0=C2=A0 =C2=A0 =C2=A0 return name=C2=A0 =C2=A0 =C2=A0 =C2=A0=C2=A0 myfunc('capitalism') Error message:=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2= =A0 =C2=A0 =C2=A0 =C2=A0 Not making sense, index is 1, letter s/b 'a'letter= to upper =3D c, index 0! if block C and index 0 1 Start: elseif block, index is 1, letter is C --------------------------------------------------------------------------- IndexError=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 = =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 Traceback (most recent cal= l last) Cell In[27], line 21 =C2=A0 =C2=A0 17=C2=A0 =C2=A0 =C2=A0 =C2=A0 # index =3D name.upper()=C2=A0 = =C2=A0 =C2=A0 =C2=A0=20 =C2=A0 =C2=A0 19=C2=A0 =C2=A0 return name=C2=A0 =C2=A0 =C2=A0 =C2=A0=20 ---> 21 myfunc('capitalism') Cell In[27], line 8, in myfunc(name) =C2=A0 =C2=A0 =C2=A0 6 while (index < howmax): =C2=A0 =C2=A0 =C2=A0 7=C2=A0 =C2=A0 if (index % 2 =3D=3D 0): ----> 8=C2=A0 =C2=A0 =C2=A0 =C2=A0 print('letter to upper =3D {}, index {}!= '.format(name[index], index)) =C2=A0 =C2=A0 =C2=A0 9=C2=A0 =C2=A0 =C2=A0 =C2=A0 name =3D name[index].uppe= r() =C2=A0 =C2=A0 10=C2=A0 =C2=A0 =C2=A0 =C2=A0 print('if block {} and index {}= '.format(name[index], index)) IndexError: string index out of range**************************************= ************* So, I'm doing something... Stupid!! *************************************************** "When you pass through the waters, I will be with you: and when you=C2=A0pa= ss through the rivers, they will not sweep over=C2=A0you. When=C2=A0you wal= k=C2=A0through the fire, you will not be burned: the flames will not set yo= u ablaze."=C2=A0 =C2=A0 =C2=A0=20 Isaiah 43:2 --=20 https://mail.python.org/mailman/listinfo/python-list =20