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From: ram@zedat.fu-berlin.de (Stefan Ram)
Newsgroups: comp.lang.python
Subject: Re: A missing iterator on itertools module?
Date: 28 Mar 2024 17:07:25 GMT
Organization: Stefan Ram
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ast <none@none.fr> wrote or quoted:
>s1 = "AZERTY"
>s2 = "QSDFGH"
>s3 = "WXCVBN"
>and I need an itertor who delivers
>A Q W Z S C E D C ...
>I didn't found anything in itertools to do the job.
>So I came up with this solution:
>list(chain.from_iterable(zip("AZERTY", "QSDFGH", "WXCVBN")))

  Maybe you meant "zip(s1,s2,s3)" as the definition of s1, s2,
  and s3 otherwise would not be required. Also the "list" is not
  necessary because "chain.from_iterable" already is an iterable.
  You could also use "*" instead of "list" to print it. So,

import itertools as _itertools
s =[ "AZERTY", "QSDFGH", "WXCVBN" ]
print( *_itertools.chain.from_iterable( zip( *s )))

  . But these are only minor nitpicks; you have found a nice solution!