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From: olcott <polcott2@gmail.com>
Newsgroups: comp.theory,sci.logic,comp.ai.philosophy
Subject: Re: ZFC solution to incorrect questions: reject them
Date: Thu, 14 Mar 2024 17:54:24 -0500
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On 3/14/2024 5:01 PM, Richard Damon wrote:
> On 3/14/24 12:01 PM, olcott wrote:
>> On 3/14/2024 11:58 AM, Ross Finlayson wrote:
>>> On 03/13/2024 10:20 PM, olcott wrote:
>>>> On 3/13/2024 1:16 PM, Ross Finlayson wrote:
>>>>> On 03/12/2024 09:00 PM, olcott wrote:
>>>>>> On 3/12/2024 10:49 PM, Ross Finlayson wrote:
>>>>>>> On 03/12/2024 08:23 PM, Ross Finlayson wrote:
>>>>>>>> On 03/12/2024 07:52 PM, olcott wrote:
>>>>>>>>> On 3/12/2024 9:28 PM, Richard Damon wrote:
>>>>>>>>>> On 3/12/24 4:31 PM, olcott wrote:
>>>>>>>>>>> On 3/12/2024 6:11 PM, Richard Damon wrote:
>>>>>>>>>>>> On 3/12/24 3:53 PM, olcott wrote:
>>>>>>>>>>>>> On 3/12/2024 5:30 PM, Richard Damon wrote:
>>>>>>>>>>>>>> On 3/12/24 2:34 PM, olcott wrote:
>>>>>>>>>>>>>>> On 3/12/2024 4:23 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>> On 3/12/24 1:11 PM, olcott wrote:
>>>>>>>>>>>>>>>>> On 3/12/2024 2:40 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>> On 3/12/24 12:02 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>> On 3/12/2024 1:31 PM, immibis wrote:
>>>>>>>>>>>>>>>>>>>> On 12/03/24 19:12, olcott wrote:
>>>>>>>>>>>>>>>>>>>>> ∀ H ∈ Turing_Machine_Deciders
>>>>>>>>>>>>>>>>>>>>> ∃ TMD ∈ Turing_Machine_Descriptions  |
>>>>>>>>>>>>>>>>>>>>> Predicted_Behavior(H, TMD) != Actual_Behavior(TMD)
>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>> There is some input TMD to every H such that
>>>>>>>>>>>>>>>>>>>>> Predicted_Behavior(H, TMD) != Actual_Behavior(TMD)
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>> And it can be a different TMD to each H.
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>> When we disallow decider/input pairs that are 
>>>>>>>>>>>>>>>>>>>>> incorrect
>>>>>>>>>>>>>>>>>>>>> questions where both YES and NO are the wrong answer
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>> Once we understand that either YES or NO is the right
>>>>>>>>>>>>>>>>>>>> answer, the whole rebuttal is tossed out as invalid and
>>>>>>>>>>>>>>>>>>>> incorrect.
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.Hq0 ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.Hqy ∞ // Ĥ applied to ⟨Ĥ⟩
>>>>>>>>>>>>>>>>>>> halts
>>>>>>>>>>>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.Hq0 ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.Hqn   // Ĥ applied to ⟨Ĥ⟩
>>>>>>>>>>>>>>>>>>> does
>>>>>>>>>>>>>>>>>>> not halt
>>>>>>>>>>>>>>>>>>> BOTH YES AND NO ARE THE WRONG ANSWER FOR EVERY Ĥ.H 
>>>>>>>>>>>>>>>>>>> ⟨Ĥ⟩ ⟨Ĥ⟩
>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>> No, because a given H will only go to one of the answers.
>>>>>>>>>>>>>>>>>> THAT
>>>>>>>>>>>>>>>>>> will be wrong, and the other one right.
>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> ∀ H ∈ Turing_Machine_Deciders
>>>>>>>>>>>>>>>>> ∃ TMD ∈ Turing_Machine_Descriptions  |
>>>>>>>>>>>>>>>>> Predicted_Behavior(H, TMD) != Actual_Behavior(TMD)
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> Not exactly. A pair of otherwise identical machines that
>>>>>>>>>>>>>>>>> (that are contained within the above specified set)
>>>>>>>>>>>>>>>>> only differ by return value will both be wrong on the
>>>>>>>>>>>>>>>>> same pathological input.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> You mean a pair of DIFFERENT machines. Any difference is
>>>>>>>>>>>>>>>> different.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Every decider/input pair (referenced in the above set) has a
>>>>>>>>>>>>>>> corresponding decider/input pair that only differs by the
>>>>>>>>>>>>>>> return
>>>>>>>>>>>>>>> value of its decider.
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> Nope.
>>>>>>>>>>>>>>
>>>>>>>>>>>>> ∀ H ∈ Turing_Machines_Returning_Boolean
>>>>>>>>>>>>> ∃ TMD ∈ Turing_Machine_Descriptions  |
>>>>>>>>>>>>> Predicted_Behavior(H, TMD) != Actual_Behavior(TMD)
>>>>>>>>>>>>>
>>>>>>>>>>>>> Every H/TMD pair (referenced in the above set) has a
>>>>>>>>>>>>> corresponding H/TMD pair that only differs by the return
>>>>>>>>>>>>> value of its Boolean_TM.
>>>>>>>>>>>>
>>>>>>>>>>>> That isn't in the set above.
>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>> That both of these H/TMD pairs get the wrong answer proves 
>>>>>>>>>>>>> that
>>>>>>>>>>>>> their question was incorrect because the opposite answer to 
>>>>>>>>>>>>> the
>>>>>>>>>>>>> same question is also proven to be incorrect.
>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>> Nope, since both aren't in the set selected.
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> When they are deciders that must get the correct answer both
>>>>>>>>>>> of them are not in the set.
>>>>>>>>>>
>>>>>>>>>> *IF* they are correct decider.
>>>>>>>>>>
>>>>>>>>>> WHen we select from all Turing Machine Deciders, there is no
>>>>>>>>>> requirement that any of them get any particular answer right.
>>>>>>>>>>
>>>>>>>>>> So, ALL deciders are in the set that we cycle through and 
>>>>>>>>>> apply the
>>>>>>>>>> following logic to ALL of them.
>>>>>>>>>>
>>>>>>>>>> Each is them paired with an input that it will get wrong, and the
>>>>>>>>>> existance of the input was what as just proven, the ^ template
>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> When they are Turing_Machines_Returning_Boolean the this
>>>>>>>>>>> set inherently includes identical pairs that only differ
>>>>>>>>>>> by return value.
>>>>>>>>>>
>>>>>>>>>> But in the step of select and input that they will get wrong, 
>>>>>>>>>> they
>>>>>>>>>> will be givne DIFFERENT inputs.
>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>>> You just don't understand what that statement is saying.
>>>>>>>>>>>>
>>>>>>>>>>>> I've expalined it, but it seems over you head.
>>>>>>>>>>>>
>>>>>>>>>>> No the problem is that you are not paying attention.
>>>>>>>>>>
>>>>>>>>>> No, you keep on making STUPID mistakes, like thinking that 
>>>>>>>>>> select a
>>>>>>>>>> input that the machine will get wrong needs to be the same for 
>>>>>>>>>> two
>>>>>>>>>> differnt machines.
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>>> For Every H, we show we can find at least one input (chosen
>>>>>>>>>>>> just for
>>>>>>>>>>>> that machine) that it will get wrong.
>>>>>>>>>>>>
>>>>>>>>>>> When we use machine templates then we can see instances of
>>>>>>>>>>> the same machine that only differs by return value where both
>>>>>>>>>>> get the wrong answer on the same input. By same input I mean
>>>>>>>>>>> the same finite string of numerical values.
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> But if they returned differnt values, they will have different
>>>>>>>>>> descriptions.
>>>>>>>>>>
>>>>>>>>>> Otherwise, how could a UTM get the right answer, since it only 
>>>>>>>>>> gets
>>>>>>>>>> the description.
>>>>>>>>>
>>>>>>>>> We can get around all of this stuff by simply using this criteria:
>>>>>>>>> Date 10/13/2022 11:29:23 AM
>>>>>>>>> *MIT Professor Michael Sipser agreed this verbatim paragraph is
>>>>>>>>> correct*
>>>>>>>>> (He has neither reviewed nor agreed to anything else in this 
>>>>>>>>> paper)
>>>>>>>>> (a) If simulating halt decider H correctly simulates its input D
>>>>>>>>> until H
>>>>>>>>> correctly determines that its simulated D would never stop running
>>>>>>>>> unless aborted then
>>>>>>>>> (b) H can abort its simulation of D and correctly report that D
>>>>>>>>> specifies a non-halting sequence of configurations.
>>>>>>>>>
>>>>>>>>> *When we apply this criteria* (elaborated above)
>>>>>>>>> Will you halt if you never abort your simulation?
>>>>>>>>> *Then the halting problem is conquered*
>>>>>>>>>
>>>>>>>>> When two different machines implementing this criteria
>>>>>>>>> get different results from identical inputs then we
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