Deutsch English Français Italiano |
<uuhpll$3dqi2$1@dont-email.me> View for Bookmarking (what is this?) Look up another Usenet article |
Path: ...!news.mixmin.net!news2.arglkargh.de!news.karotte.org!fu-berlin.de!uni-berlin.de!news.dfncis.de!not-for-mail From: Luigi Fortunati <fortunati.luigi@gmail.com> Newsgroups: sci.physics.research Subject: Re: Gravitational mass and inertial mass Date: 3 Apr 2024 06:58:33 GMT Organization: A noiseless patient Spider Lines: 18 Approved: hees@itp.uni-frankfurt.de (sci.physics.research) Message-ID: <uuhpll$3dqi2$1@dont-email.me> References: <uqts3d$1ev3g$1@dont-email.me> Reply-To: fortunati.luigi@gmail.com X-Trace: news.dfncis.de UZyiplifMOUyF3MHhTFnzg8gJZbDrEtSDlvZsv2D8c89Xeb3P+wmI4/0yY1L85Z+sP Cancel-Lock: sha1:2/L0QytCie++ynHtoljxppdne/E= sha256:/ecPq8cvDR7FXfpiETEApdfHjdxfcbdcYMdHWM5jzp0= Bytes: 1521 Luigi Fortunati il 22/02/2024 02:49:45 ha scritto: > In my animation https://www.geogebra.org/m/kqjzk5gt there are the two bodies A and B (of equal mass m) connected via an inextensible wire, ideally massless. > [[Mod. note -- This system is known as "Atwood's machine"; see > https://en.wikipedia.org/wiki/Atwood_machine > for more information. > -- jt]] My animation is not Atwood_machine because only body A moves vertically, while body B slides horizontally on a frictionless plane. > And what is the ratio between the blue force FA=mg (gravitational + inertial) and the red force FB (inertial only)? It turns out to me that FB=FA(mB/(mA+mB)) In our case where mA=mB=m, the force FB is FB=1/2 of FA. It's correct? Luigi Fortunati