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Path: ...!weretis.net!feeder9.news.weretis.net!i2pn.org!i2pn2.org!.POSTED!not-for-mail From: Richard Damon <richard@damon-family.org> Newsgroups: comp.theory Subject: Re: Can D simulated by H terminate normally? --- Date: Thu, 2 May 2024 07:04:11 -0400 Organization: i2pn2 (i2pn.org) Message-ID: <v0vrvb$2s5vs$2@i2pn2.org> References: <v0k4jc$laej$1@dont-email.me> <v0l11u$ussl$1@dont-email.me> <v0lh24$123q3$1@dont-email.me> <v0lic7$2g492$3@i2pn2.org> <v0lkas$12q0o$3@dont-email.me> <v0loq2$2g493$1@i2pn2.org> <v0lq7d$14579$2@dont-email.me> <v0ls98$2g492$7@i2pn2.org> <v0m29q$166o1$1@dont-email.me> <v0m37e$2gl1e$1@i2pn2.org> <v0m3v5$16k3h$1@dont-email.me> <v0m55t$2gl1f$3@i2pn2.org> <v0m5sn$172p4$1@dont-email.me> <v0o87n$1p7s5$1@dont-email.me> <v0oab4$1pbn5$3@dont-email.me> <v0qh21$2df66$1@dont-email.me> <v0r40q$2hb7o$5@dont-email.me> <v0t3aa$33g49$1@dont-email.me> <v0todh$3881i$2@dont-email.me> <v0ummt$2qov3$2@i2pn2.org> <v0v4i7$3l29l$13@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Thu, 2 May 2024 11:04:11 -0000 (UTC) Injection-Info: i2pn2.org; logging-data="3020796"; mail-complaints-to="usenet@i2pn2.org"; posting-account="diqKR1lalukngNWEqoq9/uFtbkm5U+w3w6FQ0yesrXg"; User-Agent: Mozilla Thunderbird X-Spam-Checker-Version: SpamAssassin 4.0.0 Content-Language: en-US In-Reply-To: <v0v4i7$3l29l$13@dont-email.me> Bytes: 3606 Lines: 65 On 5/2/24 12:24 AM, olcott wrote: > On 5/1/2024 7:28 PM, Richard Damon wrote: >> On 5/1/24 11:51 AM, olcott wrote: >>> Every D simulated by H that cannot possibly stop running unless >>> aborted by H does specify non-terminating behavior to H. When >>> H aborts this simulation that does not count as D halting. >> >> Which is just meaningless gobbledygook by your definitions. >> >> It means that >> >> int H(ptr m, ptr d) { >> return 0; >> } >> > > Your H is not simulating D at all thus not > "Every D simulated by H" quoted above Yes it is, it is just aborting the simulation before it started. After all, YOUR H stops simulating at a point based on no valid logic. Now, if you want to try to define what your simulation actually means, and also have a tighter definition of your criteria, you could make a point. Just make sure your H still meets it. IF you what a more strict version, then H needs a tiny bit of actual code to look at the first state of program D, and if it is a final state return 1 else return 0. So it becomes every program that doesn't start halted never halts. It is still a toy problem. > > Your H is not simulating D at all thus not > "Every D simulated by H" quoted above > > Your H is not simulating D at all thus not > "Every D simulated by H" quoted above > >> is always correct, because THAT H can not possible simulate the input >> to the end before it aborts it, and that H is all that that H can be, >> or it isn't THAT H. --- >> >> Unless you clarify your altered definitions, H is what H is and that >> just becomes the conclusion. >> >>> >>>> Then you can compare the definitions and try >>>> to determine whether "abnormal termination" implies halting or >>>> non-halting >>>> or neither. Note that "halting" is a freature of a Turing machine (a >>>> Turing >>>> machine halts or does not halt) but "abnormal termination" seems to be >>>> a feature of a particlar simulation (a simulation of a Truing machine >>>> is or is not abnormally terminated). >>>> >>> >> >