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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic
Subject: Richard KEEPS TRYING to get away with this falsehood
Date: Fri, 10 May 2024 16:43:56 -0500
Organization: A noiseless patient Spider
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On 5/10/2024 4:19 PM, Richard Damon wrote:
> On 5/10/24 5:11 PM, olcott wrote:
>> On 5/10/2024 3:50 PM, Richard Damon wrote:
>>> On 5/10/24 4:27 PM, olcott wrote:
>>>> On 5/10/2024 3:09 PM, Richard Damon wrote:
>>>>> On 5/10/24 1:49 PM, olcott wrote:
>>>>>> On 5/10/2024 11:12 AM, Richard Damon wrote:
>>>>>>> On 5/10/24 11:50 AM, olcott wrote:
>>>>>>>> On 5/10/2024 9:18 AM, Richard Damon wrote:
>>>>>>>>> On 5/9/24 11:10 PM, olcott wrote:
>>>>>>>>>> On 5/9/2024 9:31 PM, Richard Damon wrote:
>>>>>>>>>>> On 5/9/24 11:38 AM, olcott wrote:
>>>>>>>>>>>> On 5/8/2024 8:38 PM, immibis wrote:
>>>>>>>>>>>>> On 8/05/24 21:05, olcott wrote:
>>>>>>>>>>>>>> On 5/8/2024 10:13 AM, Mike Terry wrote:
>>>>>>>>>>>>>>> On 08/05/2024 14:01, olcott wrote:
>>>>>>>>>>>>>>>> On 5/8/2024 3:59 AM, Mikko wrote:
>>>>>>>>>>>>>>>>> On 2024-05-07 19:05:54 +0000, olcott said:
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>> On 5/7/2024 1:54 PM, Fred. Zwarts wrote:
>>>>>>>>>>>>>>>>>>> Op 07.mei.2024 om 17:40 schreef olcott:
>>>>>>>>>>>>>>>>>>>> On 5/7/2024 6:18 AM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>> On 5/7/24 3:30 AM, Mikko wrote:
>>>>>>>>>>>>>>>>>>>>>> On 2024-05-06 18:28:37 +0000, olcott said:
>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>> On 5/6/2024 11:19 AM, Mikko wrote:
>>>>>>>>>>>>>>>>>>>>>>>> On 2024-05-05 17:02:25 +0000, olcott said:
>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>> The x86utm operating system: 
>>>>>>>>>>>>>>>>>>>>>>>>> https://github.com/plolcott/x86utm enables
>>>>>>>>>>>>>>>>>>>>>>>>> one C function to execute another C function in 
>>>>>>>>>>>>>>>>>>>>>>>>> debug step mode.
>>>>>>>>>>>>>>>>>>>>>>>>> Simulating Termination analyzer H simulates the 
>>>>>>>>>>>>>>>>>>>>>>>>> x86 machine code of its
>>>>>>>>>>>>>>>>>>>>>>>>> input (using libx86emu) in debug step mode 
>>>>>>>>>>>>>>>>>>>>>>>>> until it correctly matches a
>>>>>>>>>>>>>>>>>>>>>>>>> correct non-halting behavior pattern proving 
>>>>>>>>>>>>>>>>>>>>>>>>> that its input will never
>>>>>>>>>>>>>>>>>>>>>>>>> stop running unless aborted.
>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>> Can D correctly simulated by H terminate normally?
>>>>>>>>>>>>>>>>>>>>>>>>> 00 int H(ptr x, ptr x)  // ptr is pointer to 
>>>>>>>>>>>>>>>>>>>>>>>>> int function
>>>>>>>>>>>>>>>>>>>>>>>>> 01 int D(ptr x)
>>>>>>>>>>>>>>>>>>>>>>>>> 02 {
>>>>>>>>>>>>>>>>>>>>>>>>> 03   int Halt_Status = H(x, x);
>>>>>>>>>>>>>>>>>>>>>>>>> 04   if (Halt_Status)
>>>>>>>>>>>>>>>>>>>>>>>>> 05     HERE: goto HERE;
>>>>>>>>>>>>>>>>>>>>>>>>> 06   return Halt_Status;
>>>>>>>>>>>>>>>>>>>>>>>>> 07 }
>>>>>>>>>>>>>>>>>>>>>>>>> 08
>>>>>>>>>>>>>>>>>>>>>>>>> 09 int main()
>>>>>>>>>>>>>>>>>>>>>>>>> 10 {
>>>>>>>>>>>>>>>>>>>>>>>>> 11   H(D,D);
>>>>>>>>>>>>>>>>>>>>>>>>> 12 }
>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>> *Execution Trace*
>>>>>>>>>>>>>>>>>>>>>>>>> Line 11: main() invokes H(D,D);
>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>> *keeps repeating* (unless aborted)
>>>>>>>>>>>>>>>>>>>>>>>>> Line 03: simulated D(D) invokes simulated 
>>>>>>>>>>>>>>>>>>>>>>>>> H(D,D) that simulates D(D)
>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>> *Simulation invariant*
>>>>>>>>>>>>>>>>>>>>>>>>> D correctly simulated by H cannot possibly 
>>>>>>>>>>>>>>>>>>>>>>>>> reach past its own line 03.
>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>> The above execution trace proves that (for 
>>>>>>>>>>>>>>>>>>>>>>>>> every H/D pair of the
>>>>>>>>>>>>>>>>>>>>>>>>> infinite set of H/D pairs) each D(D) simulated 
>>>>>>>>>>>>>>>>>>>>>>>>> by the H that this D(D)
>>>>>>>>>>>>>>>>>>>>>>>>> calls cannot possibly reach past its own line 03.
>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>> When you say "every H/D pair" you should specify 
>>>>>>>>>>>>>>>>>>>>>>>> which set of pairs
>>>>>>>>>>>>>>>>>>>>>>>> you are talking about. As you don't, your words 
>>>>>>>>>>>>>>>>>>>>>>>> don't mean anything.
>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>> Every H/D pair in the universe where D(D) is 
>>>>>>>>>>>>>>>>>>>>>>> simulated by the
>>>>>>>>>>>>>>>>>>>>>>> same H(D,D) that D(D) calls. This involves 1 to ∞ 
>>>>>>>>>>>>>>>>>>>>>>> steps of D
>>>>>>>>>>>>>>>>>>>>>>> and also includes zero to ∞ recursive simulations 
>>>>>>>>>>>>>>>>>>>>>>> where H
>>>>>>>>>>>>>>>>>>>>>>> H simulates itself simulating D(D).
>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>> "In the universe" is not a set. In typical set 
>>>>>>>>>>>>>>>>>>>>>> theories like ZFC there
>>>>>>>>>>>>>>>>>>>>>> is no universal set.
>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>> This template defines an infinite set of finite 
>>>>>>>>>>>>>>>>>>>> string H/D pairs where each D(D) that is simulated 
>>>>>>>>>>>>>>>>>>>> by H(D,D) also calls this same H(D,D).
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>> These H/D pairs can be enumerated by the one to ∞ 
>>>>>>>>>>>>>>>>>>>> simulated steps of D and involve zero to ∞ recursive 
>>>>>>>>>>>>>>>>>>>> simulations of H simulating itself simulating D(D). 
>>>>>>>>>>>>>>>>>>>> Every time Lines 1,2,3 are simulated again defines
>>>>>>>>>>>>>>>>>>>> one more level of recursive simulation.
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>> 1st element of H/D pairs 1 step  of D  is simulated 
>>>>>>>>>>>>>>>>>>>> by H
>>>>>>>>>>>>>>>>>>>> 2nd element of H/D pairs 2 steps of D are simulated 
>>>>>>>>>>>>>>>>>>>> by H
>>>>>>>>>>>>>>>>>>>> 3rd element of H/D pairs 3 steps of D are simulated 
>>>>>>>>>>>>>>>>>>>> by H
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>> 4th element of H/D pairs 4 steps of D are simulated 
>>>>>>>>>>>>>>>>>>>> by H
>>>>>>>>>>>>>>>>>>>> this begins the first recursive simulation at line 01
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>> 5th element of H/D pairs 5 steps of D are simulated by
>>>>>>>>>>>>>>>>>>>> next step of the first recursive simulation at line 02
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>> 6th element of H/D pairs 6 steps of D are simulated by
>>>>>>>>>>>>>>>>>>>> last step of the first recursive simulation at line 03
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>> 7th element of H/D pairs 7 steps of D are simulated 
>>>>>>>>>>>>>>>>>>>> by H
>>>>>>>>>>>>>>>>>>>> this begins the second recursive simulation at line 01
>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>> Is this the definition of the infinite set of H? We 
>>>>>>>>>>>>>>>>>>> can think of many more simulations that only these.
>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>> This template defines an infinite set of finite string 
>>>>>>>>>>>>>>>>>> H/D pairs where
>>>>>>>>>>>>>>>>>> each D(D) that is simulated by H(D,D) also calls this 
>>>>>>>>>>>>>>>>>> same H(D,D).
>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>> No-one can possibly show one element of this set where 
>>>>>>>>>>>>>>>>>> D(D) reaches
>>>>>>>>>>>>>>>>>> past its own line 03.
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> If H is a decider of any kind then the D build from it 
>>>>>>>>>>>>>>>>> reaches its line
>>>>>>>>>>>>>>>>> 4 as numberd above. Whether the simulation of D by H 
>>>>>>>>>>>>>>>>> reaches that line
>>>>>>>>>>>>>>>>> is another question.
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> *My fully operational code proves otherwise*
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> I seems like you guys don't have a clue about how infinite
>>>>>>>>>>>>>>>> recursion works. You can run the code and see that I am 
>>>>>>>>>>>>>>>> correct.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> I have one concrete instance as fully operational code.
>>>>>>>>>>>>>>>> https://github.com/plolcott/x86utm/blob/master/Halt7.c
>>>>>>>>>>>>>>>> line 555 u32 HH(ptr P, ptr I) its input in on
>>>>>>>>>>>>>>>> line 932 int DD(int (*x)())
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> HH is completely broken - it uses a global variable which 
>>>>>>>>>>>>>>> is allows HH to detect whether it is the outer HH or a 
>>>>>>>>>>>>>>> nested (simulated) HH. As a result, the nested HH behaves 
>>>>>>>>>>>>>>> completely differently to the outer HH - I mean 
>>>>>>>>>>>>>>> /completely/ differently: it goes through a totally 
>>>>>>>>>>>>>>> separate "I am called in nested mode" code path!
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> The encoding of HH is not the pure function that it needs 
>>>>>>>>>>>>>> to be to
>>>>>>>>>>>>>> be a computable function.
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> *Maybe you can settle this*
>>>>>>>>>>>>>>
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