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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic
Subject: Re: A computable function that reports on the behavior of its actual
 self is not allowed
Date: Sun, 12 May 2024 19:12:40 -0500
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On 5/12/2024 6:57 PM, Richard Damon wrote:
> On 5/12/24 7:14 PM, olcott wrote:
>> On 5/12/2024 5:40 PM, Richard Damon wrote:
>>> On 5/12/24 6:21 PM, olcott wrote:
>>>> On 5/12/2024 4:40 PM, Richard Damon wrote:
>>>>> On 5/12/24 5:18 PM, olcott wrote:
>>>>>> On 5/12/2024 2:27 PM, olcott wrote:
>>
>>>>>>> Computable functions are the basic objects of study in computability
>>>>>>> theory. Computable functions are the formalized analogue of the
>>>>>>> intuitive notion of algorithms, in the sense that a function is
>>>>>>> computable if there exists an algorithm that can do the job of the
>>>>>>> function, i.e. given an input of the function domain it can 
>>>>>>> return the
>>>>>>> corresponding output. 
>>
>>>>>>> https://en.wikipedia.org/wiki/Computable_function
>>>>>>>
>>>>>>> A computable function that reports on the behavior of its actual
>>>>>>> self (or reports on the behavior of its caller) is not allowed.
>>>>>>>
>>>>>>> A decider must halt whereas simulating a pathological input
>>>>>>> that would never halt unless aborted can only halt by aborting.
>>>>>>>
>>>>>>> This causes the direct execution of this input after it has been 
>>>>>>> aborted
>>>>>>> to have different behavior than the simulated input that cannot 
>>>>>>> possibly
>>>>>>> stop running unless aborted.
>>>>>>>
>>>>>>
>>>>>> *MORE PRECISE WORDING* (this may take a few more rewrites)
>>>>>> When Ĥ is applied to ⟨Ĥ⟩
>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
>>>>>>
>>>>>> It is a verified fact that the directly executed Ĥ ⟨Ĥ⟩ cannot 
>>>>>> possibly
>>>>>> stop running unless simulating partial halt decider embedded_H aborts
>>>>>> its simulation of its input.
>>>>>
>>>>> But since embedded_H implements a specific algorithm, either it 
>>>>> will or it won't. "unless" is a meaningless word here, it implies a 
>>>>> case that can't happen.
>>>>>
>>>>> We can look at the two possible cases.
>>>>>
>>>>> First, if embedded_H doesn't ever abort its simulation, then, as 
>>>>> you have desceribed, THAT embedded_H creates a H^ that will never 
>>>>> halt, but the H that was based on will also never abort its 
>>>>> simulation (or you lied that embedded_H is the needed copy of H) 
>>>>> and thus never answer and fail to be a decider.
>>>>>
>>>>
>>>> It can answer without halting by transitioning to its own internal
>>>> non-final state of embedded_H.qn without ever reaching Ĥ.qn. Every
>>>> simulated instance of embedded_H would do this same thing and then
>>>> continue simulating its input.
>>> So, you just don't understand how algorithms work, and how 
>>> compuations are DEFINED.
>>>
>>>
>>> If you want to try to define a new system of compuation that allows 
>>> giving answer without the algorithm ending, but still allows all the 
>>> composition operations that are included in computation theory, go 
>>> ahead and try.
>>>
>>> You then need to show that it is Turing Complete, which means that 
>>> you can't outlaw any computation allowed in a Turing Machine, like H^.
>>>
>>
>> *It <is> a way for embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ to get the correct answer*
>> *It <is> a way for embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ to get the correct answer*
>> *It <is> a way for embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ to get the correct answer*
> 
> Nope.
> 
> Claiming to do something that isn't the way defined doesn't make it work.
> 

It is not a halt decider. It is not even a termination analyzer.
It <is> an huge improvement over both YES and NO from H are the
wrong answer.  NO from H IS THE CORRECT ANSWER.

> That it like claiming you can make you cat bark, by trying to call your 
> dog a cat.
> 
>>
>> Every prior work that I have ever seen and probably every prior
>> work that exists essentially concludes that both YES and NO are the
>> wrong answer for H to provide for every H/D pair where H and D have
>> the HP pathological relationship.
> 
> Which ever answer H gives, will be wrong.
> 

I JUST PROVED OTHERWISE.
YES IS THE CORRECT ANSWER AND AS LONG AS H PROVIDES
THIS ANSWER WITHOUT STOPPING NOTHING CONTRADICTS IT.

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer